Answer: ![Area=5x^2+10x](https://tex.z-dn.net/?f=Area%3D5x%5E2%2B10x)
Step-by-step explanation:
The area of a rectangle:
×![w](https://tex.z-dn.net/?f=w)
![a=5x(x+2)](https://tex.z-dn.net/?f=a%3D5x%28x%2B2%29)
×
× ![2](https://tex.z-dn.net/?f=2)
![a=5x^2+10x](https://tex.z-dn.net/?f=a%3D5x%5E2%2B10x)
-Result:
![a=5x^2+10x](https://tex.z-dn.net/?f=a%3D5x%5E2%2B10x)
Fractions need common denominator to add or subtract them because without denominators a fraction is not a fraction, it is a whole number
Example - 2/8 is a fraction
but 2 is not a fraction
I believe that the answer is B! Hope this helps!
Answer:
x=1
y=3
Step-by-step explanation:
x+y=4
2y-4x=2
x=4-y
2y-4(4-y)=2
2y-16+4y=2
6y=18
y=3
x=4-3
x =1
so when we add to the function outside of the parentheses of (x)^3, we are moving the graph in the up down direction so it would look like x^3 but shifted up 2 units. the way to easily know which one it is, plug in zero for x in the original and 0^3 is zero so we know the original fuction will go through the origin so the function who's center is is only shifted up (because it's positive 2) two units so graph 1
note: the reason i know that what looks like a center point is actually at the origin is because f(x)= x^3 is a very famous graph that you should know the shape of :)