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3 years ago

How to solve this problem 29+12(4)

2 answers:

8 0

The answer is 77 since you would use PEMDAS and multiply 12 * 4 first to receive 48 which then adding a 29 to the 48 resulting in 77

mylen [45]3 years ago

3 0

Complete the multiplication, then add normally.

29+12(4)
29+48
=77

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Chelsea bought a computer on Monday for $1,300. Its value is predicted to decrease by $250 per year. Her brother George also bou

Elenna [48]

Answer:

The correct answer is B. George’s computer is expected to have a value of $25 greater.

Step-by-step explanation:

Since Chelsea bought a computer on Monday for $ 1,300, and its value is predicted to decrease by $ 250 per year, while her brother George also bought a computer on Monday, and the function g (x) = 1,100 - 175x predicts how the value of his computer is expected to change after x years, to determine whose computer is expected to have a greater value when it is 3 years old, and how much greater will it be, the following calculation must be performed:

Chelsea:

1,300 - (250 x 3) = X

1,300 - 750 = X

550 = X

George:

1,100 - (175 x 3) = X

1,100 - 525 = X

575 = X

Therefore, George’s computer is expected to have a value of $ 25 greater.

7 0

3 years ago

3 lines are shown. A line with points C, A, F intersects a line with points E, A, B at point A. A line extends from point A to p

Verizon [17]

Answer:

m < EAD = 29 degrees

m < CAB = 119 degrees

Given :

The question states that m < CAE = m<FAB = 61 degrees and m<DAF = 90 degrees

Solution:

1. Since line CAF and EAB intersect each other, m<CAF = m< EAF - (opposite vertical angles are equivalent)

2. m<BAC + m<EAC = 180 degrees (sum of linear pair)

3. m<CAB = 180 degrees - m<EAC

4. Equation 1: m<CAB = m<EAF = 119 degrees

5. m<EAF = m<EAD + m< DAF

6. m<EAD = m<EAF - m<DAF

7. m<EAD = 119 degrees-90 degrees = 29 degrees

Hope this helps!!! :)

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Click on this link to find his work and possibly more information of the answer. Thanks!

5 0

3 years ago

Perform the division and leave the result in trigonometric form.

Anettt [7]

Answer:

$\frac{1}{2}$ ( cos40° + isin40°)

Step-by-step explanation:

To divide

$\frac{r_{1(cosx_{1}+isinx_{1}) } }{r_{2}(cosx_{2}+isinx_{2}) }$

= $\frac{r_{1} }{r_{2} }$ [ cos(x₁ - x₂) + isin(x₁ - x₂)

Given

$\frac{2(cos90+isin90}{4(cos50+isin50)}$

= $\frac{2}{4}$ ( cos(90 - 50)° + isin(90 - 50)°

= $\frac{1}{2}$ ( cos40° + isin40° )

8 0

3 years ago

What is the constant of variation, k, of the line y = kx through (3,18) and (5,30)?

Fudgin [204]

Y is 18 so 18=3k
k=18/3
k=6 for (3,18)
for (5,30)let's see
y=30
30=5k
k=30/5
k=6

5 0

3 years ago

Read 2 more answers

Two pools are being drained. To start, the first pool had 3850 liters of water and the second pool had 4370 liters of water. Wat

SashulF [63]

Answer:

(a)

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b)

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

Step-by-step explanation:

(a) With x being the minutes after which you want to calculate the amount of water in the pool, to calculate this amount of water you must subtract the water drained from the initial amount of water that the pool contains.

Knowing that, for example, the water from the first pool drains at a rate of 33 liters per minute, then after x minutes, the total water drained will be 33 liters per minute * x minutes. Then:

Amount of water in the first pool (in liters) = 3850 liters - 33 liters per minute * x minutes

Reasoning in the same way:

Amount of water in the second pool (in liters) = 4370 liters - 43 liters per minute * x minutes

(b) Now want to know when the two pools would have the same amount of water. If they have the same amount of water then you can express:

Amount of water in the first pool = Amount of water in the second pool

Replacing the expressions found in (a):

3850 liters - 33 liters per minute * x minutes= 4370 liters - 43 liters per minute * x minutes

5 0

3 years ago