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nasty-shy [4]
3 years ago
7

A random sample of 145 students is chosen from a population of 4,250 students. The mean IQ in the sample is 130, with a standard

deviation of 7. Using a margin of error of 0.95%, what is the 90% confidence interval for the students' mean IQ score?
Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0

Answer:

Approximately, the 90% confidence interval for the students' mean IQ score is between 129.045 - 130.956

Step-by-step explanation:

The formula to use to solve this question is called the Confidence Interval formula.

Confidence interval =

x ± z × ( σ/ (√n) )

Where:

x = the sample mean = 130

z = the z-value for 90% confidence = 1.645

σ = standard deviation = 7

n = sample size = 145

130 ± 1.645 × (7/√145)

130 ± 0.9562687005

130 - 0.9562687005 = 129.0437313

130 + 0.9562687005 = 130.9562687005

Therefore, approximately, the 90% confidence interval for the students' mean IQ score is between 129.045 - 130.956

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Answer:

10.9\ \text{m/s}^2

Step-by-step explanation:

m = Masa del bloque = 18 kg

F = Fuerza en el bloque = 300 N

\mu = Coeficiente de fricción = 0.6

El equilibrio de fuerzas del sistema viene dado por

F-f=ma\\\Rightarrow 300-0.6\times 18\times 9.81=18a\\\Rightarrow a=\dfrac{300-0.6\times 18\times 9.81}{18}\\\Rightarrow a=10.9\ \text{m/s}^2

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3 years ago
What is the perimeter of a semi circle if the perimeter is 10
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It is 10 which is b so that’s the right answer
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3 years ago
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Louie made 8.1 liters of fruit punch using only grape juice and carbonated water. He used 4.2 liters of grape juice. The equatio
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3 years ago
The lee's spend $ 31 on movie tickets for 2 adults and 3 children. The Smith's spent $ 26 on movie tickets for 2 adults and 2 ch
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Answer:

Cost of adult ticket is $8 and Cost of children ticket is $5.

Step-by-step explanation:

Given:

Let the cost of each Adult ticket be 'x'.

Let the cost of each child ticket be 'y'.

Now Given:

The lee's spend $ 31 on movie tickets for 2 adults and 3 children.

Number of adult tickets = 2

Number of children ticket = 3

Total money spent = $31

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

2x+3y=31 \ \ \ \ equation \ 1

Also Given:

The Smith's spent $ 26 on movie tickets for 2 adults and 2 children

Number of adult tickets = 2

Number of children ticket = 2

Total money spent = $26

So we can say that;

Total money spent is equal to sum Number of adult tickets multiplied by cost of each Adult ticket and sum Number of children tickets multiplied by cost of each child ticket.

framing in equation form we get;

2x+2y=26 \ \ \ \ equation \ 2

Now Subtracting equation 2 from equation 1 we get;

2x+3y-(2x+2y)=31-26\\\\2x+3y-2x-2y=5\\\\y=\$5

Now substituting the value of y in equation 1 we get;

2x+3y=31\\\\2x+3\times5 =31\\\\2x+15=31\\\\2x=31-15\\\\2x=16x\\\\\frac{2x}{2}\frac{16}{2}\\\\x=\$8

Hence Cost of adult ticket is $8 and Cost of children ticket is $5.

6 0
3 years ago
The figure is made up of a cylinder, a cone, and a half sphere. The radius of the half sphere is 3 inches. What is the volume of
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=12×22 inch³

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Hope it helps...

Regards;

Leukonov/Olegion.

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