2 years ago

What’s the 10th term in 1,4,6,10

Mathematics

1 answer:

Goshia [24]2 years ago

8 0

Answer:

Step-by-step explanation:

Feb 8, 2017 - an=12n(n+1). Explanation: These are recognisable as triangular numbers, but let's use a general method for finding matching polynomial ...

1 answer

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For how many integers $n$ is it true that $\sqrt{n} \le \sqrt{4n - 6} < \sqrt{2n + 5}$?

ale4655 [162]

$\bf \sqrt{n}\leqslant \sqrt{4n-6}$

$\bf \sqrt{n}< \sqrt{2n+5}\implies \stackrel{\textit{squaring both sides}}{n< 2n+5}\implies 0\leqslant 2n - n + 5 \\\\\\ 0 < n+5\implies \boxed{-5 < n} \\\\\\ \stackrel{-5\leqslant n < 2}{\boxed{-5}\rule[0.35em]{10em}{0.25pt}0\rule[0.35em]{3em}{0.25pt}2}$