Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
113.1 =VOLUME , 4/3 X 3.14 (3) ^3 = 113.1
Answer:
dssds 8900
Step-by-step explanation:
dwdwdmunayaynd
X+8
The equation of that line from from picture is -x+4
2/2=1 with y intercept on 4
Since if is perpendicular we can assume that the equation should be positive. Eliminate the negative answers.
Negative reciprocal= x+1/4
Answer: The correct identities are: 1 + tan^2x = sec^2x 1 + cot^2x = csc^2x sin^2x + cos^2x = 1 which correspond to B and D
Step-by-step explanation:
T////T
im ok at math if its wrong im sorry T^T
