Answer:
The correct answer to the following question will be Option D.
Explanation:
- A collection of nested title scopes are defined by the class hierarchy, even though a collection of nested methodologies as well as blocks see in an everything else.
- From the all, the lexical role characterizes the connection between certain scopes of names - if method d would be decided to declare somewhere within procedure c, therefore the namespace within the namespace of c would be nested.
- The more common classes in such a family hierarchy were near the peak of the tree as well as more specific classes are towards the edges.
Other choices have no connection with the given situation. So Option D seems to be the right response.
Answer:
import java.util.Scanner;
class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
while(true) {
System.out.print("Enter an integer (0 to exit): ");
int num = scan.nextInt();
if (num == 0) break;
if (num%3 == 0 && num%5 == 0) {
System.out.printf("%d is divisable by both 3 and 5.\n", num);
}
else if (num%3 == 0 && num%5 != 0) {
System.out.printf("%d is divisable by 3 but not by 5.\n", num);
}
else if (num%3 != 0 && num%5 == 0) {
System.out.printf("%d is divisable by 5 but not by 3.\n", num);
} else {
System.out.printf("%d is not divisable by 3 or 5.\n", num);
}
}
scan.close();
}
}
Your correct answer would be Legend.
answer choice is B.
HEY THERE!!
I will chose my sister though we have not blood relation but then she is my ideal . i love her so much and i respect her a lot , much more then a real sister . She is everything to me. She guides me in my study amd after meeting her i am completely changed.
I m an INDIAN and she is an Pakistani i met up with her in brainky amd now i don't wanna loss her ever.
Love you sis .
