1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aev [14]
3 years ago
7

Why should computers have a file structure?

Computers and Technology
2 answers:
kipiarov [429]3 years ago
5 0

Answer: I know it’s A

Explanation:

I got it right on my exam

UkoKoshka [18]3 years ago
4 0
I am guessing "A" because you can store code anywhere and file structure does not prevent viruses.

hope this helped
 <span />
You might be interested in
Banking Account
satela [25.4K]

Answer:

Here is the Python script solution.

Explanation:

#!/usr/bin/python

"""Types of bank accounts"""

# Assignment:

# Bank Account Manager - Create a class called Account which will be an abstract

# class for three other classes called CheckingAccount, SavingsAccount and

# BusinessAccount. Manage credits and debits from these accounts through an ATM

# style program.

from __future__ import print_function

def pct_to_dec(num):

"""Returns decimal version of percent"""

dec = float(num) / 100

return dec

class Account(object):

"""Creates an Account"""

def __init__(self, balance, int_rate, act_type, min_balance, **kwargs):

self.balance = balance

self.int_rate = int_rate

self.act_type = act_type

self.min_balance = min_balance

super(Account, self).__init__(**kwargs)

def __str__(self):

"""Returns formatted account type and balance"""

# Charge $25 fee if balance drops below minimum

if self.balance < self.min_balance:

self.balance -= 25

# Add interest

self.balance += round(self.balance * pct_to_dec(self.int_rate), 2)

return '{0}: ${1}'.format(self.act_type, self.balance)

class CheckingAccount(Account):

"""Creates a CheckingAccount Account"""

def __init__(self, **kwargs):

super(CheckingAccount, self).__init__(**kwargs)

class SavingsAccount(Account):

"""Creates a SavingsAccount Account"""

def __init__(self, **kwargs):

super(SavingsAccount, self).__init__(**kwargs)

class BusinessAccount(Account):

"""Creates a BusinessAccount Account"""

def __init__(self, **kwargs):

super(BusinessAccount, self).__init__(**kwargs)

# pylint: disable=C0103

ca1 = CheckingAccount(balance=500, int_rate=0.25, act_type='Checking Account',

min_balance=0)

sa1 = SavingsAccount(balance=50, int_rate=0.50, act_type='Savings Account',

min_balance=0)

ba1 = BusinessAccount(balance=4000, int_rate=0.75, act_type='Business Account',

min_balance=5000)

# Month #1 statement, initial deposits plus interest

print(ca1)

print(sa1)

print(ba1)

print('-------------')

# Month #2 statement plus interest

# Make deposit into checking

setattr(ca1, 'balance', (ca1.balance + 1000))

# Withdraw from checking

setattr(ca1, 'balance', (ca1.balance - 500))

# Make a deposit into savings

setattr(sa1, 'balance', (sa1.balance + 100))

print(ca1)

print(sa1)

print(ba1)

print('-------------')

# Month #3 statement plus interest

# Make deposit into checking

setattr(ca1, 'balance', (ca1.balance + 2500))

# Withdraw from checking

setattr(ca1, 'balance', (ca1.balance - 700))

# Make a deposit into savings

setattr(sa1, 'balance', (sa1.balance + 100))

# Make a deposit into business

setattr(ba1, 'balance', (ba1.balance + 1000))

print(ca1)

print(sa1)

print(ba1)

4 0
4 years ago
Find out the names of at least 20 programming languages and their developers.
arlik [135]

Answer:

lala

Explanation:

6 0
3 years ago
Read 2 more answers
Digital citizenship is both a right and a {Blank}.
wolverine [178]
Privilege, I believe.
Hope this helps!<span />
6 0
3 years ago
Read 2 more answers
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
4 years ago
Find the propagation delay for a signal traversing the in a metropolitan area through 200 km, at the speed of light in cable (2.
Ede4ka [16]

Answer:

t= 8.7*10⁻⁴ sec.

Explanation:

If the signal were able to traverse this distance at an infinite speed, the propagation delay would be zero.

As this is not possible, (the maximum speed of interactions in the universe is equal to the speed of light), there will be a finite propagation delay.

Assuming that the signal propagates at a constant speed, which is equal to 2.3*10⁸ m/s (due to the characteristics of the cable, it is not the same as if it were propagating in vaccum, at 3.0*10⁸ m/s), the time taken to the signal to traverse the 200 km, which is equal to the propagation delay, can be found applying the average velocity definition:

v = \frac{(xf-xo)}{(t-to)}

If we choose x₀ = 0 and t₀ =0, and replace v= 2.3*10⁸ m/s, and xf=2*10⁵ m, we can solve for t:

t =\frac{xf}{v}  =\frac{2e5 m}{2.3e8 m/s} =8.7e-4 sec.

⇒ t = 8.7*10⁻⁴ sec.

4 0
3 years ago
Other questions:
  • Abigail is interested in connecting her tablet that usually connects to a wireless network, to her personal computer that usuall
    11·2 answers
  • An example of how a merge field will appear in a document is ______.
    7·2 answers
  • Is using abbreviations and symbols in social media a problem? Why or why not?
    11·1 answer
  • Effective presentations vary the color scheme on each slide.
    7·2 answers
  • Which of the following is NOT necessary for organizing data to make it easier to sort?
    6·1 answer
  • Jimmy has been issued a citation for littering in a city park. When Jimmy
    8·1 answer
  • A well-known production is making a documentary film titled “The Dwindling Population of Grizzly Bears in the United States.” Wh
    5·1 answer
  • Dr. Thomas likes to follow up with her patients to make sure they were happy with their care. She sends all patients an email en
    14·2 answers
  • Design a loop that asks the user to enter a number. The loop should iterate 10
    15·1 answer
  • What is e banking effects
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!