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3 years ago

-√64 rational or irrational?

Mathematics

2 answers:

Simora [160]3 years ago

6 0

Take the square root of 64.

You get 8.

-sqrt(64) = -8

-8 is rational since it can be written as a fraction of integers.

anzhelika [568]3 years ago

3 0

this would be rational the square root of 64 is 8 so the square root of -64 would be -8 and negative 8 ends there for making it rational.

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You have some candies in your pocket. A friend gives you five more candies. When you count all your candies you have 14

defon

Answer:

9 candies

Step-by-step explanation:

You are required to find the number of candies in your pocket

Let

x = number of candies in your pocket

A friend gives you five more candies.

Total candies = 14

This can be represented by the equation:

Total candies = candies in your pocket + candies your friend gave you

14 = x + 5

14 - 5 = x

9 = x

x = 9 candies

x = number of candies in your pocket = 9

7 0

3 years ago

Which of the following graph represents the solution set for 5x+38 ≤ 4(2-5x)

Dvinal [7]

Answer:

Option C

Step-by-step explanation:

Given inequality is,

5x + 38 ≤ 4(2 - 5x)

5x + 38 ≤ 8 - 20x [Distributive property]

5x + 20x + 38 ≤ 8 - 20x + 20x [By adding 20x on both the sides of the inequality]

25x + 38 ≤ 8

(25x + 38) - 38 ≤ 8 - 38 [By subtracting 38 on both the sides of the inequality]

25x ≤ -30

$\frac{25x}{25}\leq -\frac{30}{25}$ [Dividing by 25 on both the sides of the inequality]

x ≤ 1.2

Therefore, Option (C) will be the correct graph.

7 0

3 years ago

kylie had $5 to spend on pencils. she brought 12 pencils and had $2.12 left . how much was each pencil ?

stepan [7]

Answer:

it would be like 4 dollars and like 30 cents

Step-by-step explanation:

6 0

3 years ago

Find the common ratio of the sequence. 2, –10, 50, –250, . . .

pav-90 [236]

Common ratio = second term/first term = -10/2 = -5

3 0

4 years ago

On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a verte

statuscvo [17]

Answer:

Option 4.

Step-by-step explanation:

The vertex form of a parabola is

$g(x)=a(x-h)^2+k$ ... (1)

where, a is a constant (h,k) is vertex.

The given function is

$f(x)=x^2$

The vertex of the function is (0,0) and it goes through (-2, 4) and (2, 4).

It is given that the vertex of function g(x) is at (5,2).

Substitute h=5 and k=2 in equation.

$g(x)=a(x-5)^2+2$

g(x) is passes through (3, 6).

$6=a(3-5)^2+2$ .... (2)

$6-2=4a$

$4=4a$

Divide both sides by 4.

$a=1$

Substitute a=1 in equation (2).

$g(x)=1(x-5)^2+2$

$g(x)=(x-5)^2+2$

The function g(x) is $g(x)=(x-5)^2+2$ .

Therefor, the correct option is 4.

3 0

3 years ago

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