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MA_775_DIABLO [31]
3 years ago
12

On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a verte

x at (0, 0), and goes through (2, 4). The dashed-line parabola, labeled g of x, goes through (3, 6), has a vertex at (5, 2), and goes through (7, 6). What is the equation of the translated function, g(x), if f(x) = x2? g(x) = (x + 5)2 + 2 g(x) = (x + 2)2 + 5 g(x) = (x – 2)2 + 5 g(x) = (x – 5)2 + 2
Mathematics
2 answers:
rjkz [21]3 years ago
4 0

Answer:

g(x) = (x – 5)2 + 2

Step-by-step explanation:

D on edg

statuscvo [17]3 years ago
3 0

Answer:

Option 4.

Step-by-step explanation:

The vertex form of a parabola is

g(x)=a(x-h)^2+k                    ... (1)

where, a is a constant (h,k) is vertex.

The given function is

f(x)=x^2

The vertex of the function is (0,0) and it goes through (-2, 4) and (2, 4).

It is given that the vertex of function g(x) is at (5,2).

Substitute h=5 and k=2 in equation.

g(x)=a(x-5)^2+2

g(x) is passes through (3, 6).

6=a(3-5)^2+2             .... (2)

6-2=4a

4=4a

Divide both sides by 4.

a=1

Substitute a=1 in equation (2).

g(x)=1(x-5)^2+2

g(x)=(x-5)^2+2

The function g(x) is g(x)=(x-5)^2+2.

Therefor, the correct option is 4.

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aivan3 [116]
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