3 years ago

A dress that is normally costs 69.50 is on sale for 45% off. What is the sale price of the dress

Mathematics

2 answers:

vekshin13 years ago

5 0

$69.5 minus 45% is $38.23

Gennadij [26K]3 years ago

3 0

38.225 or when rounded 38.23

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Factor n^2+5n-24. Show that the original polynomial and the factored from describe the same sequence of numbers for n=0,1,2,3,an

Lana71 [14]

Step-by-step explanation:

We have the original equation n ^ 2 + 5 * n - 24, when factoring we have:

(n + 8) * (n - 3)

Now by replacing the values:

n = 0

0 ^ 2 + 5 * 0 - 24 = - 24

(0 + 8) * (0 - 3) = - 24

n = 1

1 ^ 2 + 1 * 0 - 24 = - 18

(1 + 8) * (1 - 3) = -18

n = 2

2 ^ 2 + 5 * 2 - 24 = - 10

(2 + 8) * (2 - 3) = - 10

n = 3

3 ^ 2 + 5 * 3 - 24 = 0

(3 + 8) * (3 - 3) = 0

n = 4

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(4 + 8) * (4 - 3) = 12

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3 years ago

7. Find x, round to nearest degree. A 15 xo 20 B.

Marizza181 [45]

Answer:37 degrees

The processed I used to solve is below. If you have an questions let me know!

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3 years ago

Which equation could have been used to create this function table? A. y = x + 1 B. y = x + 6 C. y = 5x D. y = 3x

solniwko [45]

A. y = x+1
Hope this helps :)

5 0

3 years ago

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Tamar has 24 pencils. 4/6 of the pencils need to be sharpened. How many pencils need to be sharpened?

zavuch27 [327]

Answer:

16 pencils need to be sharpened

Step-by-step explanation:

6 divided by 24 = 4 x 6 = 24 switch the 6 with a 4 and its 4 x 4= 16

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2 years ago

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Scientists were studying a rare species of parrot they went to fourth in the year 2010 and found there were 608 pairs in the for

Stells [14]

Answer:

6926 pairs in 2016.

Step-by-step explanation:

The number of pairs in t years after 2010 is modeled by the following function:

$P(t) = P(0)(1+r)^{t}$

In which P(0) is the number of pairs in 2010 and r is the growth rate, as a decimal.

608 pairs in 2010

This means that $P(0) = 608$

$P(t) = P(0)(1+r)^{t}$

$P(t) = 608(1+r)^{t}$

4617 pairs five year later.

So P(5) = 4617. We use this to find 1 + r.

$P(t) = 608(1+r)^{t}$

$4617 = 608(1+r)^{5}$

$(1+r)^{5} = \frac{4617}{608}$

$1 +r = \sqrt[5]{\frac{4617}{608}}$

$1 + r = 1.5$

$P(t) = 608(1.5)^{t}$

How many pairs in 2016?

2016 is 2016 - 2010 = 6 years after 2010. So this is P(6).

$P(t) = 608(1.5)^{t}$

$P(6) = 608(1.5)^{6} = 6926$

6926 pairs in 2016.

7 0

3 years ago