All categories

2 years ago

How can you use equations with the variable on both sides to solve real-world problems?

1 answer:

dsp732 years ago

5 0

I could join a game club for $15 and rent games for $2 each, or I could pay $3 each video rental, which is the better deal? Another example could be

You might be interested in

Please help on this equation I don't get it.

olasank [31]

Answer:

0.6 liters

Step-by-step explanation:

3 liters divided amongst 5 people comes to 0.6 liters per person. there are approximately 33.8 ounces in a liter so in ounces, everyone would get approximately 56.35 ounces of soda.

for a picture you could draw a cup with soda in it and label it to show the amount

7 0

2 years ago

This is my last question. Please help me!

sesenic [268]

Okay so first you want to simplify the given equation (7x+3y)(7x-3y)

in order to do this you multiply the first number of the first equation (7x) with the first number of the second equation (7x) this gives you 49x^2

Now you want to multiply the second number of the first equation (3y) by the second number of the second equation (-3y) this gives you -9y^2

Its as easy as pie!

3 0

2 years ago

Find the numbers b such that the average value of f(x) = 7 + 10x − 9x2 on the interval [0, b] is equal to 8.

barxatty [35]

Answer:

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

Step-by-step explanation:

The mean value of function within a given interval is given by the following integral:

$\bar f = \frac{1}{b-a}\cdot \int\limits^b_a {f(x)} \, dx$

If $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ , $a = 0$ , $b = b$ and $\bar f = 8$ , then:

$\frac{1}{b}\cdot \int\limits^b_0 {7+10\cdot x -9\cdot x^{2}} \, dx = 8$

$\frac{7}{b}\int\limits^b_0 \, dx + \frac{10}{b} \int\limits^b_0 {x}\, dx - \frac{9}{b} \int\limits^b_0 {x^{2}}\, dx = 8$

$\left(\frac{7}{b} \right)\cdot b + \left(\frac{10}{b} \right)\cdot \left(\frac{b^{2}}{2} \right)-\left(\frac{9}{b} \right)\cdot \left(\frac{b^{3}}{3} \right) = 8$

$7 + 5\cdot b - 3\cdot b^{2} = 8$

$3\cdot b^{2}-5\cdot b +1 = 0$

The roots of this polynomial are determined by the Quadratic Formula:

$b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

The numbers $b$ such that the average value of $f(x) = 7 +10\cdot x - 9\cdot x^{2}$ on the interval [0, b] is equal to 8 are $b_{1} \approx 1.434$ and $b_{2} \approx 0.232$ .

7 0

3 years ago

One morning during the spring break, Jose ran 13 miles up hill in the rain. That afternoon Jose ran up the hill 3 2/3 faster whe

netineya [11]

Answer:

The answer to your question is 13 miles

Step-by-step explanation:

In the question is not mentioned the distance that Jose one during the afternoon, it is only mentioned that he ran faster than in the morning so we can imply that the distance was the same in both occasions, just he ran faster in the afternoon because there was no rain.

6 0

2 years ago

Using a multiple of ten for at least one factor write an equation with a product that has four zeros

PtichkaEL [24]

Answer:

The required equation is : 5 · 4000 = 20,000

Step-by-step explanation:

We have to use multiple of 10 for at least one factor.

So, in order to form our equation, we take one factor as 4000 which is a multiple of 10 (10 × 400 = 4000)

And the other condition to form the equation is given that the product should contain 4 zeros, so we need to multiply the first factor 4000 by some number such that the product contains 4 zeros.

Therefore, if we multiply 4000 by 5 we get the product as 20000 which contains 4 zeros.

Hence, 5 × 4000 = 20,000 is our required equation.

8 0

2 years ago