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lutik1710 [3]
3 years ago
7

How can you use equations with the variable on both sides to solve real-world problems?

Mathematics
1 answer:
dsp733 years ago
5 0
I could join a game club for $15 and rent games for $2 each, or I could pay $3 each video rental, which is the better deal? Another example could be 
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the midpoint is AB is M(3,-2). One endpoint is A(7,-9). Find the coordinates of the other endpoint B.
cestrela7 [59]

Answer:

<em>The required points of the given line segment  are ( - 1, - 5 ).</em>

Step-by-step explanation:

Given that the line segment AB whose midpoint M is ( 3, -2 ) and point A is ( 7, - 9), then we have to find point B of the line segment AB -

As we know that-

If a line segment AB is with endpoints ( x_{1}, y_{1} ) and  ( x_{2}, y_{2}  )then the mid points M are-  

<em>M = ( \frac{ x_{1} + x_{2} }{2} , \frac{ y_{1} + y_{2}  }{2}  )</em>

Here,

<em>Let A ( 7, - 9 ), B ( x, y ) with midpoint M ( 3, - 2 ) -</em>

then by the midpoint formula M are-

<em>( 3, - 2 )  = ( \frac{ 7 + x}{2} , \frac{ - 9 + y}{2} )</em>

On comparing x coordinate and y coordinate -

We get,

<em>( \frac{ 7 + x}{2} = 3  , \frac{ - 9 + y}{2}  = - 2)</em>

<em>( 7 + x = 6, - 9 + y = - 4 )</em>

<em>( x = 6 - 7, y = - 4 + 9 )</em>

<em>( x = - 1, y = -5 )</em>

<em>Hence the required points  A are ( - 1, - 5 ).</em>

<em>We can also verify by putting these points into Midpoint formula.</em>

<em />

8 0
3 years ago
What is the length of the hypotenuse?
gayaneshka [121]

Answer:

Hello! answer: 5

Step-by-step explanation:

What you do to find the answer for these is do a^2+b^2=c^2 Basically meaning 4 × 4 + 3 × 3 will equal a number that you then find the suare root of square root just meaning a number multiplied by itself to equals that number so...

4 × 4 = 16

3 × 3 = 9

16 + 9 = 25

√25 = 5

5 × 5 = 25 therefore c = 5 hope that helps!

5 0
3 years ago
Help for this question pls :)
Lyrx [107]

Step-by-step explanation:

tan(A/2)

tan(A/2)=sinA/1+cos A

tan(A/2)= 5/13÷1+12/13

tanA/2=1/5

4 0
3 years ago
Read 2 more answers
The area of the base of the regular quadrilateral pyramid is 36 cm2 and the area of a lateral face is 48 cm2. Find: Surface area
Thepotemich [5.8K]
Surface Area (SA) = Base Area (Ab) + Lateral Area (AL)

Base Area = 36cm^2
Lateral Face Area = 48cm^2

*If this is a quadrilateral pyramid, then it has 4 lateral faces, so just multiply the "one" lateral face by 4.

Lateral Area (AL) = 4 x Lateral Face Area
-> AL = 4 x 48 = 192 cm^2

So:

SA = Ab + AL
-> SA = 36 + 192
-> Surface Area = 228 cm^2
3 0
3 years ago
-11y + 32 = 104 - 5y​
BigorU [14]
The answer is y= -12
5 0
3 years ago
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