We find the first differences between terms:
7-4=3; 12-7=5; 19-12=7; 28-19=9.
Since these are different, this is not linear.
We now find the second differences:
5-3=2; 7-5=2; 9-7=2. Then:
Since these are the same, this sequence is quadratic.
We use (1/2a)n², where a is the second difference:
(1/2*2)n²=1n².
We now use the term number of each term for n:
4 is the 1st term; 1*1²=1.
7 is the 2nd term; 1*2²=4.
12 is the 3rd term; 1*3²=9.
19 is the 4th term; 1*4²=16.
28 is the 5th term: 1*5²=25.
Now we find the difference between the actual terms of the sequence and the numbers we just found:
4-1=3; 7-4=3; 12-9=3; 19-16=3; 28-25=3.
Since this is constant, the sequence is in the form (1/2a)n²+d;
in our case, 1n²+d, and since d=3, 1n²+3.
The correct answer is n²+3
Okay, I'm pretty sure the answers are:
11) B
12) C
13) B
14) A
Answer:
7 Quarters and 3 dimes
Step-by-step explanation:
You have to find how many quarters (0.25) and dimes (0.10) are in $2.05. There are 7 quarters, which will add up to $1.75. You can't have 8 quarters because then you would have 2 dollars, and there wouldn't be enough for a dime, there would only by 5 cents left, or a nickle. Then, you find out how many nickels you need, which is 3.
.10x3=.30. 1.75+0.3=2.05.
I hope you understood:)
Answer:
Each bag originally had 35 pieces of candy
Step-by-step explanation:
Since the bags are identical, Let them Number of candies in each bag sue had be x. Thus, she had 5x candies. Since she lost 25 pieces, then she now has;
5x - 25 candies left.
We are told that Ted had 4 bags with the same number of candies like Sue had. Thus, he has 4x candies.
He mysteriously found 10 additional pieces. Total Ted now has is;. 4x + 10
Finally, we are told that Sue and Ted now have an equal number of candies.
Thus;
5x - 25 = 4x + 10
Rearranging, we have;
5x - 4x = 25 + 10
x = 35
Thus, each bag originally had 35 pieces of candy
Answer:
b
Step-by-step explanation:
its correct
