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Ksju [112]
3 years ago
7

9)Lareina understands factors. Sometimes she has trouble finding all of the factors of a number. What advice would u give Larein

a to help her find all of the factors of a number? Demonstrate by finding all of the factors of 110.
10) a. Find two numbers that have 2,3,and 5 as factors. What other factors do the two numbers have in common?

b. Find three numbers that have 2,4,and 8 as factors. What do these numbers have in common?
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0
9. It is a very good idea to divide by the smallest numbers.

First divide by 2 as many times as you can, then by 3, and so on:

110=2*55 (2 is an obvious factor, since the number ends with 0)

2*55=2*5*11 (5 is an obvious factor since the number ends with 5)


10.a

to find a number with factors 2, 3, 5, just multiply these numbers with any other number you want.

number 1: 2*3*5*4=120
number 2: 2*3*5*9=270

The greatest common factor of these 2 numbers is 2*3*5

any combination of these numbers is a common factor to number 1 and number 2, 

so these numbers have in common the factors: 

2*3=6, 3*5=15, 2*5=10, 2*3*5=30 

that is {6, 10, 15, 30}

b.

a number with 8 as a factor, has also 2 and 4 as factors.

so a number with factors 2, 4 and 8 can be found by simply multiplying 8 by any number.

number 1: 8*5=40

number 2: 8*11=88

number 3: 8*500=4,000

these numbers have in common that they all are multiples of 8 (their greatest common divisor is 8)


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The answer to the first one is y = 4/7 x − 13 /7

The second one is already in standard form

Step-by-step explanation:

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Translate to an equation and solve the product of 2 and a number increased by 8 is -48
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The equation would be 2x+8=-48 and x=-28
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-2x + 3x - 5 = 6 - 21<br><br> FIND x
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Before we do any solving, we need to simplify both sides.

On the left, we can simplify -2x + 3x - 5 to x - 5.

On the right, we can simplify 6 - 21 to -16.

So we have x - 5 = -16.

Solving from here, we add 5 to both sides to get x = -11.

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Place the numbers 0 to 8, inclusive, in the magic square so that the sum of the numbers in each row, column, and diagonal is the
ehidna [41]

Answer: See attached table

Step-by-step explanation:

\begin{table}[]\begin{tabular}{lllll} &  &  &  &  \\ &  &  &  &  \\ &  &  &  &  \\ &  &  &  & \end{tabular}\end{table}+---+---+---+

| 1 | 8 | 2 |

+---+---+---+

| 6 | 4 | 2 |

+---+---+---+

| 5 | 0 | 7 |

+---+---+---+

<u>Proofs:</u>
First row: 1+6+5 = 12

Second row: 8+4+0 = 12

Third row: 2+2+7 = 12

First column: 1+8+2 = 12

Second column: 6+4+2 = 12

Third column: 5+0+7 = 12

Diagonal starting from top left to bottom right: 1+4+7 = 12

Diagonal staring from top right to bottom left: 2+4+5 = 12

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2 years ago
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