You should find that your system doesn't have solutions. This is also confirmed by the fact that the determinant of the matrix of the coefficient of the variables x, y and z is equal to zero.
Answer:
a) Binomial distribution B(n=12,p=0.01)
b) P=0.007
c) P=0.999924
d) P=0.366
Step-by-step explanation:
a) The distribution of cracked eggs per dozen should be a binomial distribution B(12,0.01), as it can model 12 independent events.
b) To calculate the probability of having a carton of dozen eggs with more than one cracked egg, we will first calculate the probabilities of having zero or one cracked egg.

Then,

c) In this case, the distribution is B(1200,0.01)

d) In this case, the distribution is B(100,0.01)
We can calculate this probability as the probability of having 0 cracked eggs in a batch of 100 eggs.

A letter, which is how you name it. If that is what your asking, of course.
A'(1,-2)
B'(1,-3)
C'(-1,-3)
D'(-1,-2)