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Flura [38]
3 years ago
6

Melvin has game and education apps on his tablet. He noticed that he has 3 game apps for every 2 education apps. Which of the fo

llowing is another way to write this ratio?
Mathematics
2 answers:
Ierofanga [76]3 years ago
4 0
The ratio of game apps to education apps is 3:2
azamat3 years ago
3 0
The Ratio of The Game apps to education apps Is 3:2
Hope I Helped 
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Answer:

C=$7.50n + $6

Step-by-step explanation:

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What is the y-intercept of the line given by the equation below?
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The answer is C. well the y intercept is -6. and it the coordinate is 0,-6
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The length of a rectangle is (x + 1) cm and its width is 5cm less than its length.
NeX [460]

Answer:

a) the area of a square is in terms of x is

(x+1)^2 centimeter square

b)The length of the rectangle is l = (x+1)

                                       l = 7+1 =8 cm

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 =3 cm

Step-by-step explanation:

a) the area of a square is in terms of x is

 area of square is l^{2} = (x+1)(x+1)

                                 = (x+1)^2

b)  Given length is  l = (x+1) cm and

the width is 5 cm less than its length.

so we have take width is w = (x+1)-5 cm

Given area of triangle is  24 cm

Area of rectangle = length X width

24  =  (x+1)(x+1 -5 )

now simplification 24 = (x+1)^2 - 5 (x+1)

apply (a+b)^2 = a^2+2 a b+b^2

x^2+2 x+1-5 x-5 =24

x^2 -3 x -4-24=0

x^{2} -3 x -28 =0

now find factors of 28  = 7 X 4 is  

x^{2} -7 x+4 x-28=0

x(x-7)+4(x-7)=0

(x+4)(x-7)=0

x = -4 and x=7

there fore you have to choose x = 7

The length of the rectangle is l = (x+1)

                                       l = 7+1 =8

The width of the rectangle is w = [(x+1)-5]

                                     w = (7+1)-5 = 3

<u>Verification:-</u>

Given area of rectangle  = 24 = 8 X 3

                                           24 =24

so we can not choose x=-4

we have to choose x =7 only

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x^2 \ \textgreater \  49 \\  \\ &#10;x_{1,2} =  \pm \sqrt{49}  = \pm 7 \\  \\ &#10;\boxed{x \in (-\infty, ~-7)\bigcup (7,~ +\infty) }



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