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4 years ago

11

Karen and Holly took their families out to the moive theater. Karen bought three boxes of candy and two small bags of popcorn an

d paid 18.35. Holly bought four boxes of candy and three small bags of popcorn and paid 26.05.Find the cost for a box of candy.

1 answer:

Lorico [155]4 years ago

4 0

Answer:

$\large \boxed{\$2.95}$

Step-by-step explanation:

Let c = the cost of a box of candy

and p = the cost of a bag of popcorn

We have two conditions:

$\begin{array}{lrcl}(1) &3c + 2p & = & 18.35\\(2) & 4c+ 3p & = & 26.05\\\end{array}$

Calculations:

(3) 9c + 6p = 55.05

(4) <u>8c + 6p</u> =<u> 52.10</u>

c = 2.95

$\text{The cost of a box of candy is $\large \boxed{\mathbf{\$2.95 }}$}$

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3 years ago

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Answer:

$(a)\ Area = 195\pi$

$(b)\ Volume = 700\pi$

Step-by-step explanation:

Given

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$d_1 = 10$ --- lower diameter

$d_2 = 20$ --- upper diameter

Solving (a): The curved surface area

This is calculated as:

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$r_2 = 0.5 * d_2 = 0.5 * 20 = 10$ --- upper radius

And

$l = \sqrt{h^2 + (r_1 - r_2)^2$ ---- l represents the slant height of the frustrum

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$l = \sqrt{144 + 25$

$l = \sqrt{169$

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So, we have:

$Area = \pi l(r_1 + r_2)$

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Solving (b): The volume

This is calculated as:

$Volume = \frac{1}{3}\pi * h * (r_1^2 + r_2^2 + (r_1 * r_2))$

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3 years ago

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Answer:

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