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sergeinik [125]
3 years ago
10

Talulah is an ecologist who studies the change in the penguin population of Antarctica over time. She observed that the populati

on decays by a factor of 8/9 every 4 months. The population of penguins can be modeled by a function, P, which depends on the amount of time, t (in months). When Talulah began the study, she observed that there were 27,000 penguins in Antarctica. Write a function that models the population of the penguins t months since the beginning of Talulah's study. P(t) =

Mathematics
2 answers:
Oksana_A [137]3 years ago
8 0

Answer:

P(t) = 27000 * (1/9)^(t/4)

Step-by-step explanation:

This problem can me modelled with an exponencial formula:

P = Po * (1+r)^t

Where P is the final value, Po is the inicial value, r is the rate and t is the amount of time.

In this problem, we have that the inicial population/value is 27000, the rate is -8/9 (negative because the population decays), and the time t is in months, so as the rate is for every 4 months, we use the value (t/4) in the exponencial.

So, our function will be:

P(t) = 27000 * (1-8/9)^(t/4)

P(t) = 27000 * (1/9)^(t/4)

astra-53 [7]3 years ago
5 0

Answer:

P(t) = 27000 * (8/9)^(t/4)

Step-by-step explanation:

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I know you’re supposed to change the bounds and break up the integral, but for some reason, I can’t get the 44/3. Can someone ex
tatyana61 [14]

First, look for the zeroes of the integrand in the interval [0, 6] :

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• For x in (0, 2), take x = 1. Then

x² - 6x + 8 = 1² - 6•1 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

• For x in (2, 4), take x = 3. Then

x² - 6x + 8 = 3² - 6•3 + 8 = -1 < 0

so x² - 6x + 8 < 0 over this sub-interval.

• For x in (4, 6), take x = 5. Then

x² - 6x + 8 = 5² - 6•5 + 8 = 3 > 0

so x² - 6x + 8 > 0 over this sub-interval.

Next, recall the definition of absolute value:

|x| = \begin{cases}x & \text{for }x \ge0 \\ -x & \text{for }x < 0\end{cases}

Then from our previous analysis, this definition tells us that

|x^2 - 6x + 8| = \begin{cases}x^2 - 6x + 8 & \text{for }0

So, in the integral, we have

\displaystyle \int_0^6 |x^2-6x+8| \, dx = \left\{\int_0^2 - \int_2^4 + \int_4^6\right\} (x^2 - 6x + 8) \, dx

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and the overall integral would be

20/3 - (-4/3) + 20/3 = 44/3

3 0
3 years ago
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