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Vika [28.1K]
3 years ago
11

What additional info do you need

Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0

Answer:

  ∠C ≅ ∠M  or  ∠B ≅ ∠L

Step-by-step explanation:

You are given an angle and its opposite side as being congruent. AAS requires two congruent angles and one side, so you need another set of congruent angles (one in each triangle). It does not matter which they are. The above-listed pairs are appropriate.*

_____

* Since the figure cannot be assumed to be drawn to scale, either of angles B or C could be declared congruent to either of angles L or M. However, it appears that angles B and L are opposite the longest side of the triangle, so it makes good sense to declare that pair congruent. The same congruence statement (ΔBCD≅ΔLMN) would result from declaring angles C and M congruent. So, either declaration will work (matches the last answer choice.)

__

AAS requires two angles and a side. One side is already marked, so we do not need any more information about sides. (The second and third answer choices can be rejected as irrelevant.)

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25+5 Times blank equals 35
mezya [45]
Let x = blank

25 + 5x = 35

5x = 35 - 25

5x = 10

x = 10/5

x = 2

Done!
6 0
3 years ago
1. What is the slope of the graph? (HINT: Pay close attention to what the x and y axes are counting by!) 2. What does the slope
lidiya [134]

Slope = -4/5

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hope this helped a little

6 0
3 years ago
Solve for R<br><br> 3 r + 4 <br> ---------- = 5 <br> 2<br><br> r = ?
lakkis [162]
To find r, first write out the equation:
\frac{3r+4}{2} =5
Next, multiply both sides by 2:
3r+4=10
Now, subtract both sides by 4:
3r = 6
Divide both sides by 3:
r=2

The answer to this problem is r = 2. Hope this helps and have a phenomenal day!
6 0
3 years ago
Read 2 more answers
What's the answer for this question? (The numbers after the letters are indexes btw) 27a9 x 18b5 x 4c2 Over 18a4 x 12b2 x 2c
zysi [14]

Answer:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

Step-by-step explanation:

Given

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Required

Simplify

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c}

Cancel out 18

\frac{27a^9 * b^5 * 4c^2 }{a^4 * 12b^2 * 2c}

Divide 4 and 2

\frac{27a^9 * b^5 * 2c^2 }{a^4 * 12b^2 *c}

Divide 27 and 12 by 3

\frac{9a^9 * b^5 * 2c^2 }{a^4 * 4b^2 *c}

Apply law of indices

\frac{9a^{9-4} * b^{5-2} * 2c^{2-1} }{4}

\frac{9a^5 * b^3 * 2c }{4}

Divide 2 and 4

\frac{9a^5 * b^3 * c}{2}

\frac{9a^5b^3c}{2}

Rewrite as:

\frac{9}{2}a^5b^3c

Hence:

\frac{27a^9 * 18b^5 * 4c^2 }{18a^4 * 12b^2 * 2c} = \frac{9}{2}a^5b^3c

4 0
2 years ago
What is the slope that crosses through the point (-4,-5) and (6,8)
Angelina_Jolie [31]
Slope = \frac{Y2 - Y1}{X2 - X1}

\frac{8 - (-5)}{6 - (-4)}

Your final answer is: \frac{13}{10}
5 0
3 years ago
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