Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
Step-by-step explanation:
<em><u>The correct question is</u></em>
The sum of three consecutive even integers is -72. what are the three numbers
Let
x ----> the first consecutive even integer
x+2 ----> the second consecutive even integer
x+4 ----> the third consecutive even integer
we know that
solve for x
so
therefore
the numbers are
Answer:
70?
Step-by-step explanation:
4:5 8:10 12:15 that some eqivelent ratios
