Answer:
   y = 2x−2
Step-by-step explanation:
You are given a slope and a point, so you can write the equation using point-slope form:
   y -k = m(x -h) . . . . . . a line with slope m through point (h, k)
Putting in the numbers given, you have ...
   y -6 = 2(x -4)
   y = 2x -8 +6 . . . . eliminate parentheses, add 6
   y = 2x -2 . . . . . . . collect terms.
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You know that the slope is the coefficient of x, so the first choice is eliminated right away. Trying the point values in the other equations shows you that they only work for the last choice, as shown above.
- 2·4 +14 = 22 ≠ 6 . . . . second choice doesn't work
- 2·4 +6 = 14 ≠ 6 . . . . . third choice doesn't work
- 2·4 -2 = 6 . . . . . . y = 2x-2 is the equation that works
 
        
                    
             
        
        
        
Answer:
9/7
Step-by-step explanation:
 
        
             
        
        
        
Reason:
1. Given
2. Angles opposite by the vertex
3. Two pair of corresponding angles are congruent (∠C ≅∠E and <span>∠ABC≅∠DBE)</span>
        
                    
             
        
        
        
Answer:

Step-by-step explanation:
Notice that we can get from the x-coordinate of A, 1, to the x-coordinte of A', -2, by subtracting 3 from the x-coordinate of A. More formaly:



Similarly, we can get from the y-coordinate of A, 5, to the y-coordinate of A', 3, by subtracting 2 from the y-coordinte of A. More formaly:



Now we now that to get to A' from A, we need to subtract 3 to the x-coordinate of A and subtract 2 to the y-coordinate. Knowing this, we can create the expression to translate any point of the polygon ABCD to create the polygon A'B'C'D':

 
        
             
        
        
        


keep in mind, that "t" is the time when the train at A station, left towards B station
they met, at some time "t", and by the time that happened, train from A
which started 3 hours earlier, had already covered "d" distance,
whatever that is
and the train coming from B, covered, 600-d, or the difference