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3 years ago

Write each decimal using a negative exponent.

Mathematics

2 answers:

leonid [27]3 years ago

8 0

Answer:

The answer to your question is below

Step-by-step explanation:

When using scientific notation,

- when we move the decimal point to the right, the power will be negative.

- when we move the decimal point to the left, the power will be positive.

a) 0.00001 move the decimal point 5 places to the right 1 x 10⁻⁵

b) 0.001 move the decimal point 3 places to the right 1 x 10⁻³

mr Goodwill [35]3 years ago

3 0

Answer:

10^-5
10^-3

Step-by-step explanation:

You know from place values that ...

0.00001 = 1/100,000 = 1/10^5 = 10^-5

and

0.001 = 1/1000 = 1/10^3 = 10^-3

_____

The applicable rule of exponents is ...

1/a^b = a^-b

_____

The place-value chart attached ends at 10^-4, but you can see from what is there what the pattern is.

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the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room

Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

$C.S.A.=2h(l+b)$

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

$C.S.A.=\text{Perimeter of the base} \times h$

Putting the given values, we get

$C.S.A.=18\times 3$

$C.S.A.=54$

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0

3 years ago

When the outliers are removed, how does the mean change? dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1 on 81, 2 o

sveticcg [70]

We can plot this data on MS Excel and determine the distribution of these data reflected on the graph. Among these numbers, 50 is the outlier since it is very far from the other numbers ranging from 76 to 83. We can perform interquartile range to determine or verify the outliers in the data set. In this respect, we can see that there is not much distribution seen. The average of all data sets is equal to 96.25. When the outlier (50) is removed, we expect the mean to become higher since a low number was ommitted including high numbers only. Outliers are obtained from special causations such as human errors.