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krok68 [10]
2 years ago
14

Please help me find where I should draw the line! Thsm!

Mathematics
2 answers:
STatiana [176]2 years ago
6 0
1st one: a point on (0,0) for the Y intercept, then go up 2 over 1 which will bring you to (1,2) and i don’t k ow how many points you need so i’ll give a 3rd one, up 2, over 1 will land you at (2,4)

2nd one: a point at (0,4) for the y intercept (at end of equation) then move up 1, over 1, that will bring you to (1,1) and do it again to get (2,2)

Anastasy [175]2 years ago
5 0

Answer:

That should be it if I'm not mistaken. The first one is y= 4+x, and the second one is y= 2x

Step-by-step explanation:

Can I get Brainliest if I'm right?

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aalyn [17]

Slope intercept form: y = 2/3x + 7

Standard form: 2x - 3y = -21

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3 years ago
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Which statement is true about points located in quadrant l on the coordinate plane
OverLord2011 [107]

Answer:

D

Step-by-step explanation:

Quadrant 1 is located in the upper right hand corner with x values traveling right (positive) and y values traveling up (positive)

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2 years ago
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I NEED HELP ASAP!!! Two angles are supplementary. The measure of one angle is 6 less than 20% of the other. find both angles.
Mamont248 [21]

Answer:

Step-by-step explanation:

3 0
3 years ago
2x − y = 3
const2013 [10]

Answer:

a. Infinitely many solutions

Step-by-step explanation:

The given equations are  2x - y = 3

4x = 6 + 2y

We can use substitution method to solve these system of equations.

2x - y = 3

y = 2x - 3

Now plug in y = 2x - 3 in the second equation, we get

4x = 6 + 2(2x - 3)

4x = 6 + 4x  - 6

4x = 4x

Here we get infinitely many solution.

Both the equations are the same.

Thank you.

5 0
3 years ago
The sum of three numbers is 86 the second number is 9 less than the first the third number is 3 times the first what are the num
Kobotan [32]

Answer:

10, 19 and 57

Step-by-step explanation:

let the first number be a, the second be b and the third be c

a+b+c=86

the second number is 9 less than the first

a=b+9------i

b=a-9

the third number is 3 times the first

c=3a------ii

a=c/3

therefore

b+9=c/3

c=3(b+9)

b+9+b+3(b+9)=86

b+9+b+3b+27=86

collecting like terms

5b=86-(27+9)

5b=86-36

5b=50

therefore

b=10

recall i to solve for a

a=b+9

a=10+9

a=19

recall ii to solve for c

c=3a

c=3*19

c=57

7 0
3 years ago
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