Here is how I would show the work for this problem
5- (a-4) = 3 (a+2)
5-a+4 = 3*a+3*2
5-a+4 = 3a+6
-a+9 = 3a+6
-a+9+a = 3a+6+a
9 = 4a+6
9-6 = 4a+6-6
3 = 4a
4a = 3
4a/4 = 3/4
a = 3/4
So the solution is the fraction a = 3/4 (in decimal form 0.75)
Let me know if you have any questions or issues with any of the steps shown above. It's a lot to take in so feel free to ask about anything really.
Answer:
4dogs and no wolves
Step-by-step explanation:
when a dog is taken care of (Trained) it could be let to run free in a definite region.
On a plane with one line we can place two dogs (one dog in each of the regions) and they will not fight as they will be separated by a line, and they will run free.
If we place three lines in general, then we would have four regions where 4 dogs can run free as they are separated by a line so as not to fight.
But for Wolves from the question it is deduced that: A wolf has to be caged all the time and no matter how well you train a wolve, it wont yield to instructions.
With these two, wolves wont be allowed on the plane at all.
We use x to represent the price of the cheapest hat. Since the more expensive hat is twice the price of the cheaper one, we use 2x to represent it. Therefore x + 2x, or 3x, equals $75.12. Divide 75.12 by 3 to find x, which is 25.04. The more expensive hat is 2x, so we must multiply 25.04 by 2 to find the price of the more expensive hat. Therefore, the cost is $50.08.
Answer:
see explanation
Step-by-step explanation:
Since AC = BC then ΔABC is isosceles with base angles
∠BAC =∠ABC, thus
3x + x = 70
4x = 70 ( divide both sides by 4 )
x = 17.5
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∠ADC is an external angle of ΔABD and the external angle is equal to the 2 opposite interior angles, hence
y = 70 + x = 70 + 17.5 = 87.5
