Answer:
See explanation below.
Step-by-step explanation:
First, obtain the percentage of sales tax for a sale. Say it is 5%.
Then, obtain the sale prices, for two items say they are: $25.00 and $15.00.
Add the amounts together to obtain the subtotal:
$25.00 + $15.00 = $40.00, is the subtotal.
Multiply the amount by the percentage:
$40.00 * 5% =
40 * .05 = $2.00, is the sales tax
Add the tax to the subtotal to obtain the total amount to pay:
$40.00 + $2.00 = $42.00, is the total amount to pay.
Hope this helps!! Have an Awesome Day!! :-)
(x² + 4x - 45)/(x² + 10x + 9)
<span>
Numerator = N = x² + 4x - 45 </span>
= x² + 9x - 5x - 45
= (x² + 9x) - (5x + 45)
= x(x + 9) - 5(x + 9)
= (x + 9)(x - 5)
<span>
Denominator = D = x² + 10x + 9 </span>
= x² + x + 9x + 9
= (x² + x) + (9x + 9)
= x(x + 1) + 9(x + 1)
= (x + 1)(x + 9)
<span>
Hence, the given expr. = N/D </span>
= {(x + 9)(x - 5)}/{(x + 1)(x + 9)
= (x - 5)/(x + 1)
<span>
Restrictions : x ≠ - 1, x = 5 </span>
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Wait what is there a question
Answer:
(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.
(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.
Step-by-step explanation:
We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1
Let X = <u><em>the blood platelet counts of a group of women</em></u>
So, X ~ Normal(
)
Now, the empirical rule states that;
- 68% of the data values lie within the 1 standard deviation of the mean.
- 95% of the data values lie within the 2 standard deviations of the mean.
- 99.7% of the data values lie within the 3 standard deviations of the mean.
(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.
(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;
z-score of 443.9 =
=
= 3
z-score of 71.3 =
=
= -3
So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.