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olchik [2.2K]
3 years ago
12

Can someone help me with this asap please, thanks!

Mathematics
1 answer:
kvv77 [185]3 years ago
5 0

Answer:

Given: r\perp s and t\perp s.

Prove: r\parallel t

Since r\perp s, By the definition of perpendicular lines angles 1, 2, 3 and 4 are 90 degree. similarly t\perp s,  it means angles 5, 6, 7 and 8 are 90 degree.

We can say that,

\angle 1\cong \angle 5, \angle 2\cong \angle 6, \angle 3\cong \angle 7 and \angle 4\cong \angle 8

From figure it is noticed that the angle 1 and 5 are corresponding angles.

If two parallel lines are intersected by a transversal, then the corresponding angles are equal.

Since corresponding angles are congruent, therefore the line must be parallel to each other.

Hence proved that r\parallel t.

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g= 3 1/2 (#D)

Step-by-step explanation:

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13. The numerator of a rational number is 3 less than the denominator. If the denominator is
g100num [7]

Fraction = 4/7

Step by step Explanation

Let the denominator be x.

Numerator = 3 less than denominator

denominator = x

Numerator = (x – 3)

Now, Adding 5 to denominator

adding 2 to numerator.

Numerator = (x – 3 + 2)

Denominator = (x + 5)

(x – 3 + 2)/(x + 5)

According to the question

 (x – 3 + 2)/(x + 5) = 1/2

(x – 1)/(x + 5) = 1/2

2(x – 1) = 1(x + 5)

2x – 2 = x + 5

2x – x = 5 + 2

x = 7

So,

=> Denominator x = 7

=> Numerator (x – 3) => (7 – 3) = 4

= > Fraction = 4/7

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