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rosijanka [135]
2 years ago
6

45.6 kg = ____ dag I will make you brainliest

Mathematics
2 answers:
marysya [2.9K]2 years ago
7 0

Answer:

45.6

Step-by-step explanation:

i looked it up for you

Anarel [89]2 years ago
3 0

Answer:

it will be 4560

Step-by-step explanation:

1 kg equals 100 dag

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Convert 212 degree Fahrenheit into degree Celsius<br>I will mark them as brainlists<br>​
Simora [160]

Answer:

The answer might be 100° c

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3 years ago
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mel-nik [20]

Answer:

y=5/1 - 3

Step-by-step explanation:

use rise over run

8 0
2 years ago
8. A triangle has sides with lengths of 6, 8, and 10 units, and a square has a
svet-max [94.6K]

Difference between the area of the triangle and square is 25

Step-by-step explanation:

  • Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.

Area of the triangle = \sqrt{s (s-a)(s-b)(s-c)} where s = \frac{a + b + c}{2}

⇒ s = (6 + 8 + 10)/2 = 24/2 = 12

\sqrt{s(s-a)(s-b)(s-c)} = \sqrt{12(12-6)(12-8)(12-10)}

                                    = \sqrt{12(6)(4)(2)} = \sqrt{576} = 24 sq. units

  • Step 2: Find the area of the square with perimeter = 28 units.

Perimeter of the square = 4 × side = 28

⇒ Side of the square = 28/4 = 7 units

⇒ Area of the square = (side)² = 7² = 49 sq. units

  • Step 3: Find the difference between the area of the square and triangle.

Difference = 49 - 24 = 25

8 0
3 years ago
Help answering this question please
IrinaK [193]
The transformation from 1 to 2 is a translation, as the shape is moved from one point to another with no rotation, reflection, or change in size.

The transformation from 2 to 3 is a reflection, as the shape is now upside down. It is still the same distance from the y-axis.

The answer is D. translation, then reflection.
3 0
3 years ago
Read 2 more answers
(1+cos2x)/(1-cos2x) = cot^2x
sesenic [268]

We will turn the left side into the right side.

\dfrac{1 + \cos 2x}{1 - \cos2x} = \cot^2 x

Use the identity:

\cos 2x = \cos^2 x - \sin^2 x

\dfrac{1 + \cos^2 x - \sin^2 x}{1 - ( \cos^2 x - \sin^2 x)} = \cot^2 x

\dfrac{1 - \sin^2 x + \cos^2 x }{1 - \cos^2 x + \sin^2 x} = \cot^2 x

Now use the identity

\sin^2 x + \cos^2 x = 1 solved for sin^2 x and for cos^2 x.

\dfrac{\cos^2 x + \cos^2 x }{\sin^2 x + \sin^2 x} = \cot^2 x

\dfrac{2\cos^2 x}{2\sin^2 x} = \cot^2 x

\dfrac{\cos^2 x}{\sin^2 x} = \cot^2 x

\cot^2 x = \cot^2 x


8 0
3 years ago
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