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3 years ago

(See The Picture To Know The Problem, also it's REALLY bad)

Mathematics

1 answer:

Sophie [7]3 years ago

4 0

The answer would be the second option , B

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Can anyone help with 1-10

Alex787 [66]

Answer:

1. E

2. A

3. B

4. AB

5. E

6. D

7. BC

8. CD

9. A

10. C

Step-by-step explanation:

6 0

3 years ago

Consider the lengths of the sides of a triangle as listed. Triangle A: 3, 4, 5 Triangle B: 5, 12, 13 Triangle C: 10, 12, 15 Tria

insens350 [35]

Answer:

Triangle E or D

Step-by-step explanation:

Is not the right one

6 0

3 years ago

PLs help 50 PTS!!!!! PLEASE ILL GIVE BRAINLIEST!!!!!

Nookie1986 [14]

Answer:

$\large\boxed{y=\dfrac{1}{4}x^2-x-4}$

Step-by-step explanation:

The equation of a parabola in vertex form:

$y=a(x-h)^2+k$

(h, k) - vertex

The focus is

$\left(h,\ k+\dfrac{1}{4a}\right)$

We have the vertex (2, -5) and the focus (2, -4).

Calculate the value of a using $k+\dfrac{1}{4a}$

k = -5

$-5+\dfrac{1}{4a}=-4$ add 5 to both sides

$\dfrac{1}{4a}=1$ multiply both sides by 4

$4\!\!\!\!\diagup^1\cdot\dfrac{1}{4\!\!\!\!\diagup_1a}=4$

$\dfrac{1}{a}=4\to a=\dfrac{1}{4}$

Substitute

$a=\dfrac{1}{4},\ h=2,\ k=-5$

to the vertex form of an equation of a parabola:

$y=\dfrac{1}{4}(x-2)^2-5$

The standard form:

$y=ax^2+bx+c$

Convert using

$(a-b)^2=a^2-2ab+b^2$

$y=\dfrac{1}{4}(x^2-2(x)(2)+2^2)-5\\\\y=\dfrac{1}{4}(x^2-4x+4)-5$

use the distributive property: a(b+c)=ab+ac

$y=\left(\dfrac{1}{4}\right)(x^2)+\left(\dfrac{1}{4}\right)(-4x)+\left(\dfrac{1}{4}\right)(4)-5\\\\y=\dfrac{1}{4}x^2-x+1-5\\\\y=\dfrac{1}{4}x^2-x-4$

3 0

3 years ago

I have no idea how to or how I would even start to write a problem like this, Please help.

TEA [102]

That's an easy one! The year would be Monday Janurary 27th, 3000 and it would be the year of the monkey!

8 0

3 years ago

Find the area AC = 8m, BD = 6m

grandymaker [24]

Answer:

24 m²

Step-by-step explanation:

The area of a rhombus is the product of the two diagonals over 2

A= (8*6)/2 = 24 m²

5 0

3 years ago