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3 years ago

What is the perimeter of the entire football field including the end zone

Mathematics

2 answers:

MrMuchimi3 years ago

8 0

whats the question?

then i might be able to help you

Dmitry [639]3 years ago

4 0

Answer:

346 2/3 yards

Step-by-step explanation:

A football field is 100 yards long with each end zone being 10 years long, meaning the total length is 120 yards.

The width is 53 1/3 yards.

The perimeter is all the sides added, and a rectangle's, the shape of the field's, formula is p = 2l + 2w.

So if we plug it in and add it all up:

120 + 120 + 53 1/3 + 53 1/3

Perimeter = 346 2/3

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3 years ago

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5 0

3 years ago

Read 2 more answers

1 Point

I am Lyosha [343]

Option C

The ratio for the volumes of two similar cylinders is 8 : 27

<h3><u>Solution:</u></h3>

Let there are two cylinder of heights "h" and "H"

Also radius to be "r" and "R"

$\text { Volume of a cylinder }=\pi r^{2} h$

Where π = 3.14 , r is the radius and h is the height

Now the ratio of their heights and radii is 2:3 .i.e

$\frac{\mathrm{r}}{R}=\frac{\mathrm{h}}{H}=\frac{2}{3}$

<em><u>Ratio for the volumes of two cylinders</u></em>

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{\pi r^{2} h}{\pi R^{2} H}$

Cancelling the common terms, we get

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{\mathrm{r}}{R}\right)^{2} \times\left(\frac{\mathrm{h}}{\mathrm{H}}\right)$

Substituting we get,

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\left(\frac{2}{3}\right)^{2} \times\left(\frac{2}{3}\right)$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{2 \times 2 \times 2}{3 \times 3 \times 3}$

$\frac{\text {Volume of cylinder } 1}{\text {Volume of cylinder } 2}=\frac{8}{27}$

Hence, the ratio of volume of two cylinders is 8 : 27

7 0

3 years ago