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Complete Question
The life of a semiconductor laser at a constant power is normally distributed with a mean of 7,000 hours and a standard deviation of 600 hours. If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is closest to? Assuming percentile = 95%
Answer:
0.125
Step-by-step explanation:
Assuming for 95%
z score for 95th percentile = 1.645
We find the Probability using z table.
P(z = 1.645) = P( x ≤ 7000)
= P(x<Z) = 0.95
After 7000 hours = P > 7000
= 1 - P(x < 7000)
= 1 - 0.95
= 0.05
If three lasers are used in a product and they are assumed to fail independently, the probability that all three are still operating after 7,000 hours is calculated as:
(P > 7000)³
(0.05)³ = 0.125
Answer:
BC is just 3d+7??
Step-by-step explanation:
Answer:
the answer should be always, which would be b
Step-by-step explanation:
if you have a reciprocal 3/2 then the fraction would be 2/3 which is proper. you just flip the numbers.
Answer:
Always multiply the first number with 3 and then add two to the next number. And so on..
Step-by-step explanation:
Answer:
y=-5x+12
Step-by-step explanation:
just use a graphing calculator and basic knowledge of slope intercept form
