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4 years ago

5

Joe ran 8 laps for a total of 1 mile. How many laps is 5/8 of a mile?

1 answer:

REY [17]4 years ago

7 0

Answer:

5

Step-by-step explanation:

their is 8 laps and 5/8 would be five laps

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PLZZ HELPP WILL GIVE BRAINLIEST Graph the line y=25x+3. Use the line tool and select two points on the line. THIS IS A K12 TEST

Sophie [7]

Step-by-step explanation:

you can use any value either in place of x or y to find the corresponding coordinate but if you want to find the x and y intercept you can desigate x as zero and find the y intercept and vice versa.

so to find x and y intercept

y=25x+3. to find x intercept designate y as zero

0=25x+3

-3=25x

x= -3/25. p( -3/25,0)

y=25x+3 to find y intercept designate x as zero

y=25(0)+3

y=3. p(0,3)

the above y and x intercept indicates the points that the line of equation pass through when drawn graphically.

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3 years ago

kelly and 3 friends collected seashells at the beach. Working together, they collected 8 1/2 buckets of seashells. They divide t

Tju [1.3M]

Answer:

2 1/8 buckets each

Step-by-step explanation:

5 0

4 years ago

(a + b + c) power of 10 - abc<br><br><br><br> Tip <br> A=1<br> B=2<br> C= -3

kicyunya [14]

$\\ \rm\longmapsto (a+b+c)^{10}-abc$

$\\ \rm\longmapsto (1+2-3)^{10}-(1)(2)(-3)$

$\\ \rm\longmapsto (3-3)^{10}+6$

$\\ \rm\longmapsto 0^{10}+3$

$\\ \rm\longmapsto 0+3$

$\\ \rm\longmapsto 3$

4 0

3 years ago

Read 2 more answers

Anyone want my rare brainly username ( harmful )

Paul [167]

Answer:

thx lm.ao ill friend you

Step-by-step explanation:

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3 years ago

Suppose u and v are functions of x that are differentiable at x=0 and that u(0)=4, u′(0)=7, v(0)=2 and v′(0)=1. Find the values

Leona [35]

Answer with Step-by-step explanation:

We are given that u and v are functions of x and both are differentiable at x=0

$u(0)=4,u'(0)=7,v(0)=2,v'(0)=1$

a.We have to find the values of $\frac{d(uv)}{dx}$

$\frac{d(u\cdot v)}{dx}=u'v+uv'$

Using this formula

Then , we get

$[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18$

$[\frac{d(uv)}{dx}]_{x=0}=18$

b. $\frac{d(u/v)}{dx}=\frac{u'v-uv'}{v^2}$

$[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}$

$[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}$

c.

$[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}$

$[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}$

d. $\frac{d(-6v-9u)}{dx}=-6v'-9u'$

$[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69$

$[\frac{d(-6v-9u)}{dx}]_{x=0}=-69$

3 0

3 years ago