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mr Goodwill [35]
3 years ago
12

Fis = 0.4 and fst = 0.8 and the average allele frequency p = 0.7, find the observed level of heterozygosity in the total populat

ion.
a..2689,
b..3743,
c..0504,
d..9827,
e..5001
Mathematics
1 answer:
olga2289 [7]3 years ago
3 0
Option c should be right

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5. If f(X) = 2X^2 g(X) = 3X - 9 Find (f*g)(X)
Dmitry [639]

Answer:

the final answer will be:

6x^3 -9

4 0
3 years ago
What are four equivalent expressions for 42+18
Vinvika [58]
42+18=60

so
30+30
20+40
10+50
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this should work:)
3 0
3 years ago
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my partner and I are at coordinates (-20,15) on a map. If our destination is (35,-12) a. what are the coordinates of the rest st
Dennis_Churaev [7]

A) midpoint would be (-20+35)/2, (15-12)/2

= (15/2, 3/2)


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Nick puts $10 into his lunch money on Monday and spends $2.00 each day until his balance reaches 0
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5 Days

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5 0
4 years ago
What is the denominator of the simplified expression? (StartFraction 2 n Over 6 n + 4 EndFraction) (StartFraction 3 n + 2 Over 3
Alexeev081 [22]

Answer:

<h3>The denominator of the given simplified expression is 3n-2</h3>

Step-by-step explanation:

Given expression is (\frac{2n}{6n+4})(\frac{3n+2}{3n-2})

<h3>To find the denominator of the simplified expression :</h3>

First simplify the given expression as below ;

(\frac{2n}{6n+4})(\frac{3n+2}{3n-2})

=(\frac{2n}{2(3n+2)})(\frac{3n+2}{3n-2}) ( here by taking the common term 2 outside the factor )

=(\frac{n}{1})(\frac{1}{3n-2}) ( here by simplifying the factors )

=\frac{n}{3n-2}

Therefore (\frac{2n}{6n+4})(\frac{3n+2}{3n-2})=\frac{n}{3n-2}

Therefore the result of the  given  simplified expression is \frac{n}{3n-2}

<h3>The denominator of the given simplified expression is 3n-2</h3>
8 0
4 years ago
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