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Pepsi [2]
3 years ago
7

Help me pls thank you alot!

Mathematics
2 answers:
damaskus [11]3 years ago
4 0
Your answer will be -1/7
Rainbow [258]3 years ago
4 0
Answer -1/7..........
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The cost for an order of 100 kilograms of steel bars is $230. The cost for an order of 150 kilograms of steel bars is $320. Writ
luda_lava [24]

Answer:

y = 9x/5 + 50

Step-by-step explanation:

We are represent the information as coordinate (x,y)

If the cost for an order of 100 kilograms of steel bars is $230, this is expressed as (100, 230)

Also if the cost for an order of 150 kilograms of steel bars is $320, this is expressed as;

(150, 320)

Find the equation of a line passing through the points. The standard form of the equation is expressed as y = mx+c

m is the slope

c is the intercept

Get the slope;

m = y2-y1/x2-x1

m = 320-230/150-100

m = 90/50

m = 9/5

Get the y-intercept by substituting m = 9/5 and any point say (100, 230) into the expression y = mx+c

230 = 9/5(100)+c

230 = 9(20)+c

230 = 180 + c

c = 230-180

c = 50

Get the required equation

y = mx+c

y = 9/5 x + 50

Hence an equation for the cost of an order of steel bars (y) in terms of the weight of steel bars ordered (x) is y = 9x/5 + 50

4 0
3 years ago
Lucia estimates the attendance at the middle school concert to be 267. The actual attendance is 304.
USPshnik [31]

Answer:

12%

Step-by-step explanation:

Divide 267 by 304

Lucia got 88% correct

Lucia got 12% Incorrect

3 0
3 years ago
Ms hills travels 2400 miles at a rate of 400 miles per day to visit her grandchild . Write and solve an equation to find the num
Naya [18.7K]

It Would Take her 6 days

2400÷400=6

6 0
3 years ago
Break apart 372*7 multiplication
Alona [7]
372 simplified is: 2*2*3*31. Thus, 372*7= 2*2*3*31*7. I believe that's what the question is asking for, Hope that helps. :)
7 0
3 years ago
Read 2 more answers
For Each Data Set, Determine the median, the first and third Quartiles, and the interquartile Range.
inysia [295]
Text per day: median= 26 1st quartile= 19 3rd quartile=38 Interquartile=19 Daily attendance: median=357.5 1st quartile=298 3rd quartile=422 Interquartile= 124
4 0
3 years ago
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