Answer:
Part 4) Right triangle
Part 5) Kite
Step-by-step explanation:
Part 4) What kind of triangle is made by connecting the points A(0, –6), B(3, –6), and C(3, –2)?
Using a graphing tool
see the attached figure N 
The triangle of the figure is not equilateral------> The triangle does not have three equal sides
The triangle of the figure is a right triangle------>The triangle has an angle of 
The triangle of the figure is not isosceles------> The triangle does not have two equal sides
The triangle of the figure is not a right and isosceles
Part 5) What type of quadrilateral is formed by connecting the points
?
Using a graphing tool
see the attached figure N
The figure is not a rhombus------> All sides are not congruent
The figure is not a trapezoid-----> has not parallel sides
The figure is a kite------> Two disjoint pairs of consecutive sides are congruent and the diagonals meet at a right angle
Answer:
Horizontal distance = 1218.41 ft
Step-by-step explanation:
Given data:
Slope distance = 1223.88 ft
Zenith angle is = 95°25'14"
converting zenith angle into degree
Zenith angle is
94.421°
Horizontal distance
putting all value to get horizontal distance value
Horizontal distance 
Horizontal distance = 1218.41 ft
The attached graph represents the solution set of 
<h3>How to determine the graph?</h3>
The complete options are not given.
So, I would plot the graph that represents the solution set
The inequality is given as:

Start by splitting the inequalities as follows:


The above means that we plot the graphs of f(x) and g(x) to represent the solution set
See attachment
Read more about inequalities at:
brainly.com/question/25275758
#SPJ1
C: none of these are solutions to the given equation.
• If<em> y(x)</em> = <em>e</em>², then <em>y</em> is constant and <em>y'</em> = 0. Then <em>y'</em> - <em>y</em> = -<em>e</em>² ≠ 0.
• If <em>y(x)</em> = <em>x</em>, then <em>y'</em> = 1, but <em>y'</em> - <em>y</em> = 1 - <em>x</em> ≠ 0.
The actual solution is easy to find, since this equation is separable.
<em>y'</em> - <em>y</em> = 0
d<em>y</em>/d<em>x</em> = <em>y</em>
d<em>y</em>/<em>y</em> = d<em>x</em>
∫ d<em>y</em>/<em>y</em> = ∫ d<em>x</em>
ln|<em>y</em>| = <em>x</em> + <em>C</em>
<em>y</em> = exp(<em>x</em> + <em>C </em>)
<em>y</em> = <em>C</em> exp(<em>x</em>) = <em>C</em> <em>eˣ</em>