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3 years ago

Marissa dug three fifths of a hole in one tenth of an hour. Find the rate in holes per hour

Mathematics

1 answer:

snow_lady [41]3 years ago

3 0

Answer:

Step-by-step explanation:

This might be easier to do in decimals. Let's try it.

3/5 = 0.6

1/10 = 0.1

rate = holes / hours

rate = 0.6/0.1

rate = 6 holes per hour

Try it with fractions.

rate = $\frac{\frac{3}{5} }{\frac{1}{10} }$ Invert and multiply the 1/10

rate = $\frac{3}{5} *\frac{10}{1}$ = 30/5 = 6

It's the same answer. Pick the method that you feel most comfortable with.

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What is the value of 2²+5²

BartSMP [9]

Answer:

Step-by-step explanation:

2^2 + 5^2

PEMDAS

Exponents first

4+25

Then add

3 0

3 years ago

Add the equations.<br> 3x - y = -1<br> - 3x + 3y= 27

harkovskaia [24]

Step-by-step explanation:

3x - 3x -y + 3y = 27-1

2y = 26

y = 13 use this to find the value of x

3x - 13 = -1

3x = -1 + 13

3x = 12

x = 4

3 0

3 years ago

Find a recursive formula for the sequence:<br><br> 1, -1, -7, -25

Mumz [18]

<h3>Answer:</h3>

$a_n=3a_{n-1}-4$

<h3>Step-by-step explanation:</h3>

<em>Try the answers</em>

You can try the answers to see what works. You can expect all of the choices to match the first two terms, so try some farther down. Let's see if we can get -25 from -7.

a) 3*(-7) -4 = -21 -4 = -25 . . . . this one works

b) -7 -2 = -9 . . . . ≠ -25

c) -3(-7) +2 = 21 +2 = 23 . . . . ≠ -25

d) -2(-7) +1 = 14 +1 = 15 . . . . ≠ -25

The formula that works is the first one.

_____

<em>Derive it</em>

All these formulas depend on the previous term only, so we can write equations that show the required relationships. Let the unknown coefficients in our recursion formula be p and q, as in ...

$a_n=p\cdot a_{n-1}+q$

Then, to get the second term from the first, we have

... 1·p +q = -1

And to get the third term from the second, we have

... -1·p +q = -7

Subtracting the second equation from the first gives ...

... 2p = 6

... p = 3 . . . . . . . this is sufficient to identify the first answer as correct

We can find q from the first equation.

... q = -1 -p = -1 -3 = -4

So, our recursion relation is ...

$a_n=3a_{n-1}-4$

6 0

3 years ago

subset to real numbers, and as you can see are not at all connected to the rest of numbers (and integers).

Natali5045456 [20]

Irrational numbers are the subset of real numbers that are not at all connected to the rest of numbers.

The subsets of real numbers are natural numbers, whole numbers, integers, rational numbers and irrational numbers.

Natural numbers are subset of whole numbers, which are subset of integers, which are subset of rational numbers. Hence, all of them are interconnected. The set of irrational numbers is the only subset of real numbers which is not associated with the rest.

For example:-

1 is a natural number, whole number, integer, rational number but not irrational number. On the other hand, $\sqrt{2}$ is an irrational number but none of the rest.