We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer:
the cost of each pen is 1.33
Step-by-step explanation:
if you multiply 0.75 by 8 you get 6 after that you subtract 6 from 12.65 which means you have 6.65 which you divide by 5 which equals 1.33
You can graph that by looking at the y-intercept first. That's where you start to put a point in the coordinate plane or graph.
So go down 1 below 0.
Next, look at the slope.
We know that y = -2x - 1 is in slope intercept form (y = mx+b)
So -2 is our slope. It will be -2/1 because we need a fraction to graph the rise over run and all whole numbers can be a fraction by making 1 as their denominator.
Look at the attachment.
Starting from -1 (y-intercept), go down 2 (-2) then right 1 (1).
To complete the line above, keep the same value and reverse their sign/symbol. So -2/1 will be 2/-1. It goes up 2 then left 1.
I hope you understand and find this answer the most helpful! :)