Twice the number G is 2×G.
The difference between 2G and 10 is 24.
2G - 10 = 24
2G = 24 + 10
2G = 34
G = 34/2
G = 17
(x+4)(x+6)=0
x = -4, x=-6
The answer is C.
Answer:
a. Emily should begin her turn as the third driver at point (1, -0.5).
b. Emily's turn to drive end at point (-2.5, -3.75).
Step-by-step explanation:
Let assume that the group of girls travels from their hometown to San Antonio in a straight line. We know that each location is, respectively:
Hometown

San Antonio

Then, we can determine the end of each girl's turn to drive by the following vectorial expression based on the vectorial equation of the line:
Steph
(1)
![S(x,y) = (8,6) + \frac{1}{4}\cdot [(-6,-7)-(8,6)]](https://tex.z-dn.net/?f=S%28x%2Cy%29%20%3D%20%288%2C6%29%20%2B%20%5Cfrac%7B1%7D%7B4%7D%5Ccdot%20%5B%28-6%2C-7%29-%288%2C6%29%5D)


Andra
(2)
![A(x,y) = (8,6) + \frac{2}{4}\cdot [(-6,-7)-(8,6)]](https://tex.z-dn.net/?f=A%28x%2Cy%29%20%3D%20%288%2C6%29%20%2B%20%5Cfrac%7B2%7D%7B4%7D%5Ccdot%20%5B%28-6%2C-7%29-%288%2C6%29%5D)


Emily
(3)
![E(x,y) = (8,6) + \frac{3}{4}\cdot [(-6,-7)-(8,6)]](https://tex.z-dn.net/?f=E%28x%2Cy%29%20%3D%20%288%2C6%29%20%2B%20%5Cfrac%7B3%7D%7B4%7D%5Ccdot%20%5B%28-6%2C-7%29-%288%2C6%29%5D)


a. <em>If the girls take turns driving and each girl drives the same distance, at what point should they stop from Emily to begin her turn as the third driver? </em>
Emily's beginning point is the Andra's stop point, that is,
.
Emily should begin her turn as the third driver at point (1, -0.5).
b. <em>At what point does Emily's turn to drive end?</em>
Emily's turn to drive end at point (-2.5, -3.75).
-14.9 =

- 2.1 (Add 2.1 to both sides)
-12.8 =

(Multiply both sides by 8)
-102.4 = x
~~~Hope this helps!~~~
First, we have
s1/r1 = s2/r2
The question also states the fact that
s/2πr = θ/360°
Rearranging the second equation, we have
s/r = 2πθ/360°
Then we substitute it to the first equation
s1/r1 = 2πθ1/360°
s2/r2 = 2πθ2/360°
which is now
2πθ1/360° = 2πθ2/360°
By equating both sides, 2π and 360° will be cancelled, therefore leaving
θ1 = θ2