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natali 33 [55]
3 years ago
7

Anyone with a knee injury or any doctor! What does it mean if my knee popped locked up all in like 1.5 seconds and then it now h

urts to bend but not alot and i can wiggle my kneecap like a lot. This is the 2nd time in like 7-9 months! Please help! Comment if there is no more answers left!
Mathematics
2 answers:
Aloiza [94]3 years ago
8 0
This happened to me last year, my knee was dislocated. Please go get it checked out immediately I avoid further damage!
geniusboy [140]3 years ago
3 0
So my knee pops out of place all of the time because the track in my knee is messed up and the best thing for it is to stretch it out when you can and get a knee brace from cvs because they are cheap but work very well. For stretches do ones that focus on hamstrings and make sure you stretch it out before any physical activity to prevent it popping out again. Hope this helped and feel better!
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The diffrence of a number m and 30 is 10
viktelen [127]
M - 30 = 10

so the number has to be 10 more than 30.

30+ 10 = m


m = 40
8 0
3 years ago
What is the ratio 1.12 turned in to a fraction in simplest form?
vagabundo [1.1K]
1.12=1 12/100=1 3/25 
         or 28/25
4 0
3 years ago
Factor 10c^2-60cd +80d^2
ozzi
10c^2-60cd +80d^2

(2c - 8d) (5c -10d)

this  \\ is \\ because...

2c*5c=10c^2

2c * -10d=-20cd \\ -8d*5c=-40cd \\ -20cd-40cd=-60cd

-8d * -10d = 80d
5 0
3 years ago
Point K on the number line shows Kelvin's score after the first round of a quiz: A number line is shown from negative 10 to 0 to
Ierofanga [76]

Answer:

The correct option is;

3 + (-9) = -6, because -6 is 9 units to the left of 3

Step-by-step explanation:

The given information are;

Kelvin's score after the first round is shown at point K on the number line

The range of numbers on the number line = -10 to +10

The position of point K after the first round = +3

The number of points Kevin lost in the second round = 9 points

Therefore, Kevin's cumulative score = +3 - 9 = -6

Therefore, the expression that shows how many total points he has at the end is of round 2 = 3 + (-9) = -6, because -6 is 9 units to the left of 3.

7 0
3 years ago
Suppose instead of comparing independent measurements taken from two groups, you used a matched-pairs experiment and one treatme
lina2011 [118]

You should use a T distribution to find the critical T value based on the level of confidence. The confidence level is often given to you directly. If not, then look for the significance level alpha and compute C = 1-alpha to get the confidence level. For instance, alpha = 0.05 means C = 1-0.05 = 0.95 = 95% confidence

Use either a table or a calculator to find the critical T value. When you find the critical value, assign it to the variable t.

Next, you'll compute the differences of each pair of values. Form a new column to keep everything organized. Sum everything in this new column to get the sum of the differences, which then you'll divide that by the sample size n to get the mean of the differences. Call this dbar (combination of d and xbar)

After that, you'll need the standard deviation of the differences. I recommend using a calculator to quickly find this. A spreadsheet program is also handy as well. Let sd be the standard deviation of the differences

The confidence interval is in the form (L, U)

L = lower bound

L = dbar - t*sd/sqrt(n)

U = upper bound

U = dbar + t*sd/sqrt(n)

3 0
3 years ago
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