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4 years ago

10

The product of 4 and n translate.

1 answer:

NikAS [45]4 years ago

7 0

I think the answer would be 4n

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$1.12 for 8.2 ounces

Leno4ka [110]

What about it
what is the question

3 0

3 years ago

Read 2 more answers

Write an expression for the volume of a rectangularprism if the length is 25 cm shorter than some given amount, x, and the width

seraphim [82]

The volume of a prism is given by:

$V=lwh$

We know that the height is x. The length is 25 shorter than x, this can be express as:

$x-25$

The width is 14 longer than x, this can be express as:

$x+14$

Plugging the expressions for the length, the width and the height we have that:

$\begin{gathered} V=(x-25)(x+14)x \\ V=x(x-25)(x+14) \end{gathered}$

Therefore, the volume of the prism is:

$V=x(x-25)(x+14)$

8 0

1 year ago

Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 25% of the passengers are on business while

MArishka [77]

Answer:

Answer:

The probability is $P(J|B) = 0.36$

Step-by-step explanation:

B =business

J=jumbo

Or =ordinary

From the question we are told that

The proportion of the passenger on business in the ordinary jet is $P(B| Or) = 0.25$

The proportion of the passenger on business in the jumbo jet is $P(B|J) = 0.30$

The proportion of the passenger on jumbo jets is $P(j) = 0.40$

The proportion of the passenger on ordinary jets is evaluated as

$1 - P(J) = 1- 0.40 = 0.60$

According to Bayer's theorem the probability a randomly chosen business customer flying with Global is on a jumbo jet is mathematically represented as

$P(J|B) = \frac{P(J) * P(B|J)}{P(J ) * P(B|J) + P(Or ) * P(B|Or)}$

substituting values

$P(J|B) = \frac{ 0.4 * 0.25}{0.4 * 0.25 + 0.6 * 0.3}$

$P(J|B) = 0.36$

Step-by-step explanation:

8 0

3 years ago

Solve using the Pythagorean identity<br>

Lynna [10]

<h3> $\bold{Sin\theta_{1}=-\frac{4}{5}}$ </h3>

Answer:

Solution given

Cos $\displaystyle \theta_{1}=\frac{3}{5}$

consider Pythagorean theorem

$\bold{Sin²\theta+Cos²\theta=1}$

Subtracting $Cos²\theta$ both side

$\displaystyle Sin²\theta=1-Cos²\theta$

doing square root on both side we get

$Sin\theta=\sqrt{1-Cos²\theta}$

Similarly

$Sin\theta_{1}=\sqrt{1-Cos²\theta_{1}}$

Substituting value of $Cos\theta_{1}$

we get

$Sin\theta_{1}=\sqrt{1-(\frac{3}{5})²}$

<h3>Solving numerical</h3>

$Sin\theta_{1}=\sqrt{1-(\frac{9}{25})}$

$Sin\theta_{1}=\sqrt{\frac{16}{225}}$

$Sin\theta_{1}=\frac{\sqrt{2*2*2*2}}{\sqrt{5*5}}$

$Sin\theta_{1}=\frac{4}{5}$

Since

In IVquadrant sin angle is negative

$\bold{Sin\theta_{1}=-\frac{4}{5}}$

7 0

3 years ago

Read 2 more answers

Which of the following rates converts to a unit rate of $12.50 per hour?

Tems11 [23]

I think the answer would be (A.)

7 0

3 years ago