If <em>x</em> is the smallest of the three, then the next two integers are <em>x</em> + 2 and <em>x</em> + 4.
"Twice the largest is 20 less than the sum of all three" translates to
2 (<em>x</em> + 4) = (<em>x</em> + (<em>x</em> + 4) + (<em>x</em> + 6)) - 20
Solve for <em>x</em> :
2<em>x</em> + 8 = 3<em>x</em> - 10
<em>x</em> = 18
Then the three numbers are {18, 20, 22}.
Answer:look below
Step-by-step explanation:Let x, x+2 & x+4 be the 3 integers.
x+2(x+2)=(x+4)+20
x+2x+4=x+4+20
3x+4=x+24
3x-x=24-4
2x=20
The answer is x equals 1/2.
Answer:
maggie
Step-by-step explanation:
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