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taurus [48]
2 years ago
13

Find three consecutive even integers so that twice the largest

Mathematics
2 answers:
vekshin12 years ago
7 0

If <em>x</em> is the smallest of the three, then the next two integers are <em>x</em> + 2 and <em>x</em> + 4.

"Twice the largest is 20 less than the sum of all three" translates to

2 (<em>x</em> + 4) = (<em>x</em> + (<em>x</em> + 4) + (<em>x</em> + 6)) - 20

Solve for <em>x</em> :

2<em>x</em> + 8 = 3<em>x</em> - 10

<em>x</em> = 18

Then the three numbers are {18, 20, 22}.

viktelen [127]2 years ago
5 0

Answer:look below

Step-by-step explanation:Let x, x+2 & x+4 be the 3 integers.

x+2(x+2)=(x+4)+20

x+2x+4=x+4+20

3x+4=x+24

3x-x=24-4

2x=20

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Option A

2x^2(6x-1) + 3(6x-1) is one way to determine the factors of 12x^3-2x^2+18x-3 by grouping

<em><u>Solution:</u></em>

Factoring by grouping means that you will group terms with common factors before factoring

<em><u>Given expression is:</u></em>

12x^3-2x^2+18x-3

Group the first two terms together and then the last two terms together.

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We can see that 2x^2 is common in first two terms

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