Find three consecutive even integers so that twice the largest

Mathematics

2 answers:

vekshin12 years ago

7 0

If x is the smallest of the three, then the next two integers are x + 2 and x + 4.

"Twice the largest is 20 less than the sum of all three" translates to

2 (x + 4) = (x + (x + 4) + (x + 6)) - 20

Solve for x :

2x + 8 = 3x - 10

x = 18

Then the three numbers are {18, 20, 22}.

viktelen [127]2 years ago

5 0

Answer:look below

Step-by-step explanation:Let x, x+2 & x+4 be the 3 integers.

x+2(x+2)=(x+4)+20

x+2x+4=x+4+20

3x+4=x+24

3x-x=24-4

2x=20

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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

Pavel [41]

$\boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$

<h2>Explanation:</h2>

Using the quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ \\ Here: \\ \\ f(x) = x^2 + 5x + 5 \\ \\ \\ So: \\ \\ a=1 \\ \\ b=5 \\ \\ c=5 \\ \\ \\ x=\frac{-5 \pm \sqrt{5^2-4(1)(5)}}{2(1)} \\ \\ x=\frac{-5 \pm \sqrt{25-20}}{2} \\ \\ x=\frac{-5 \pm \sqrt{5}}{2} \\ \\ \\ Two \ solutions: \\ \\ \boxed{x_{1}=\frac{-5 + \sqrt{5}}{2}} \\ \\ \\ \boxed{x_{2}=\frac{-5 - \sqrt{5}}{2}}$