Find three consecutive even integers so that twice the largest
2 answers:
If <em>x</em> is the smallest of the three, then the next two integers are <em>x</em> + 2 and <em>x</em> + 4.
"Twice the largest is 20 less than the sum of all three" translates to
2 (<em>x</em> + 4) = (<em>x</em> + (<em>x</em> + 4) + (<em>x</em> + 6)) - 20
Solve for <em>x</em> :
2<em>x</em> + 8 = 3<em>x</em> - 10
<em>x</em> = 18
Then the three numbers are {18, 20, 22}.
Answer:look below
Step-by-step explanation:Let x, x+2 & x+4 be the 3 integers.
x+2(x+2)=(x+4)+20
x+2x+4=x+4+20
3x+4=x+24
3x-x=24-4
2x=20
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The answer to your question is A
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GH = -6 + 2(8) = 10.
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Answer:
The answer is 35
Step-by-step explanation:
If you do 15 divided by 3/7 you herb 35 you can check it by doing 3/7 of 35 and you get 15
