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4 years ago

What is 0.58 as a fraction

Mathematics

2 answers:

zvonat [6]4 years ago

7 0

0.58
= 58/100
= 29/50

wlad13 [49]4 years ago

3 0

Here is the answer: 58 over 100, hope it helps.

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An oval track is made by endosing semicircles on each end of a 50 m by 100 m rectangle. Find the area endowed by the track. Use

Aleks [24]

Answer:

Step-by-step explanation:

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3 years ago

I need help finding slope for this both

Svetllana [295]

Answer 1: C. m + 7 less than or equal to 40

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3 years ago

The set M represents multiples of 4 from 6 to 38. M=8,12,16,20,24,28,32,36 The set N represents even numbers from 4 to 13. N=4,6

Tomtit [17]

Answer:

The correct option is B. 2

So there are two elements that is 8, 12 in the set M⋂N .

Step-by-step explanation:

Given:

M is a set of multiples of 4 from 6 to 38

i.e M = { 8, 12, 16, 20, 24, 28, 32,36 }

N is a set of even numbers from 4 to 13

i.e N = { 4, 6, 8, 10, 12 }

To Find:

M⋂N = ?

Solution:

Set:

A set is a well-defined collection of distinct objects, considered as an object in its own right.

Examples :

M is a set of multiples of 4 from 6 to 38

i.e M = { 8, 12, 16, 20, 24, 28, 32,36 }

N is a set of even numbers from 4 to 13

i.e N = { 4, 6, 8, 10, 12 }

M⋂N = set of those numbers which are present in M as well as in N

∴ M⋂N = { 8, 12 }

So there are two elements that is 8, 12 in the set M⋂N .

8 0

3 years ago

Using the diagram, what is the value of x?

galben [10]

The answer is A.120
Because 60+60 +60 is 180
180-60 is 120

8 0

3 years ago

Read 2 more answers

+5x+3.

Nimfa-mama [501]

<h3><u>Question:</u></h3>

2x^2 + 5x + 3

What are the factors of the polynomial?

(2x+3)(x+1)

(2x-3)(x-1)

(3x+2)(x+1)

(3x-2)(x-1)

<h3><u>Answer:</u></h3>

<em><u>Option A</u></em>

<em><u>The factors are:</u></em>

$2x^2+5x+3 = (2x+3)(x+1)$

<h3><u>Solution:</u></h3>

Given that, the quadratic equation is:

$2x^2 + 5x + 3$

We have to find the factors of polynomial

<h3><u>Find the factors:</u></h3>

$2x^2+5x+3$

Split 5x as 2x and 3x

$2x^2+5x+3 = 2x^2 +2x + 3x + 3$

$\mathrm{Break\:the\:expression\:into\:groups}$

$2x^2+5x+3=\left(2x^2+2x\right)+\left(3x+3\right)$

$\mathrm{Factor\:out\:}2x\mathrm{\:from\:}2x^2+2x\mathrm{:\quad }2x\left(x+1\right)$

Thus we get,

$2x^2+5x+3 = 2x(x+1) + (3x+3)$

$\mathrm{Factor\:out\:}3\mathrm{\:from\:}3x+3\mathrm{:\quad }3\left(x+1\right)$

Thus we get,

$2x^2+5x+3 = 2x(x+1) + 3(x+1)$

$\mathrm{Factor\:out\:common\:term\:}x+1$

Thus we get,

$2x^2+5x+3 = (2x+3)(x+1)$

Thus the factors are found for given polynomial

4 0

3 years ago