Answer:
Area = 32/3
Step-by-step explanation:
x = u
²
y = uv
z = 12v
²
0 ≤ u ≤ 2
0 ≤ v ≤ 1
Since ru = <2u, v, 0> and rv = <0, u, 24v>, we have
Where ru is the differentiation of x, y, z with respect to u and rv is the differentiation of x, y, z wit respect to v.
we find the cross product of ru and rv
ru × rv = 24v²i - 48uv²j + 2u²k
absolute value of ru × rv = 2u² + 24v²
We can now find the area
∫₀² du ∫₀¹ dv (2u² + 24v²) = ∫₀² du [2u²v + 8v³]₀¹ = 32/3
Detailed description can be found in the attachment
1.6666666 and so on and so forth
Answer:
Step-by-step explanation:
<u>Given:</u>
<u>Solving for x:</u>
Answer: hi , these are the 3 answers in order : X, 36 & 15.75
Step-by-step explanation: