<h3><u>Solution: </u></h3>
Radius of Cylindrical Pillar , r = 28 Cm = 0.28 m.
Curved surface area of a Cylindrical = 2πrh.
Curved surface area of a pillar -
Curved surface area of 24 such Pillar :-
(7.04 x 24 = 168.96m²)..
- Cost of painting an area of 1 m² = Rs8...
• Therefore , cost of painting 1689.6m² :-
( 168.96 x 8 = Rs 1351.68)...
Answer:
Step-by-step explanation:
The estemit will be 0
10x-20=10x-20, make your decision on the answer from this which they are all real numbers. Hope this will help you!
Question 6
Given:
QR = RS
QR = x + 6
RS = 4x
To find:
Length of line segment QS
Steps:
We know QR = RS, so substituting we get,
x + 6 = 4x
6 = 4x - x
6 = 3x
6/3 = x
2 = x
x = 2
Now,
QS = QR + RS
QS = x + 6 + 4x
QS = 2 + 6 + 4(2)
QS = 2 + 6 + 8
QS = 8 + 8
QS = 16 units
Therefore, the length of QS is 16 units
Question 7
Given:
QR = RS
QR = 2x - 2
RS = 2x
To find:
Length of line segment QS
Steps:
We know that QR = RS, so substituting the values we get,
QR = RS
3x - 2 = 2x
3x - 2 - 2x = 0
3x - 2x = 2
x =2
Now,
QS = QR + RS
QS = 3x - 2 + 2x
QS = 3(2) - 2 + 2(2)
QS = 6 - 2 + 2(2)
QS = 6 - 2 + 4
QS = 4 + 4
QS = 8 units
Therefore, the length of QS is 8 units
Happy to help :)
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