3 years ago

Enter the slope-intercept equation of the line that has slope -6 and y-intercept (0, 2).

1 answer:

3 0

In y = mx + b form, the m is ur slope and the b is ur y int.

so ur equation in slope intercept form with a slope of -6 and a y int of 2 is :
y = -6x + 2

You might be interested in

In which quadrant is the number 6 – 8i located on the complex plane?

antoniya [11.8K]

The number 6 – 8i is located in the 4th quadrant on the complex plane.

4 0

3 years ago

Read 2 more answers

A right triangle has legs that are 11 inches and 13 inches long.What is the area of the triangle?

Citrus2011 [14]

Just use your right angled triangle formula.

A= $\frac{ab}{2}$

Plug n chug

A= $\frac{11*13}{2}$
A=71.5 $in^{2}$

5 0

3 years ago

Given that f(x) = 19x2 + 152, solve the equation f(x) = 0

telo118 [61]

Option A

The solution is:

$x = \pm 2i \sqrt{2}$

Solution:

$f(x) = 19x^2+152$

We have to solve the equation f(x) = 0

Let f(x) = 0

$0=19x^2+152$

Solve the above equation

$19x^2 + 152 = 0$

$\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8$

Take square root on both sides

$x = \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}$