Hello :
the discriminat of each quadratic equation : ax²+bx+c=0 ....(a <span>≠ 0) is :
</span><span>Δ = b² -4ac
1 ) </span>Δ > 0 the equation has two reals solutions : x = (-b±√Δ)/2a
2 ) Δ = 0 : one solution : x = -b/2a
3 ) Δ <span>< 0 : no reals solutions
in this exercice : x² = 5-x
x² +x-5 = 0 .... a =1 b= 1 c=-5
calculate </span>Δ..................................
Answer:
perpendicular line through a point on a line
Step-by-step explanation:
The circle centered at C seems intended to produce point D at the same distance as point B. That is, C is the midpoint of BD.
The circles centered at B and D with radius greater than BC seems intended to produce intersection points G and H. (It appears accidental that those points are also on circle C. As a rule, that would be difficult to do in one pass.)
So. points G and H are both equidistant from points B and D. A line between them will intersect point C at right angles to AB.
Segment GH is perpendicular to AB through point C (on AB).
Answer:
x=3/8
Step-by-step explanation:
2*x=3/4
x=3/4*2
x=3/8
Answer:
a= 1
b= 3
c= 2
d= 2
e= 6
f= 8. These are the answers for the question. Love from Gauthmath