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rjkz [21]
3 years ago
10

What are the coordinates of the midpoint of the line segment with end points J (-6, 3) and K (4, -2)

Mathematics
1 answer:
iVinArrow [24]3 years ago
7 0

Answer:

(-1 , 1.5)

Step-by-step explanation:

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Work out the third term of the sequence with nth term 3(n+2).<br><br>​
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Answer:

Step-by-step explanation:

n = 3

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irina1246 [14]

Answer:

A

Step-by-step explanation:

So we have the equation:

3(x-4)^\frac{4}{3}+16=64

First, let's subtract 16 from both sides:

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Now, let's divide both sides by 3:

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Remember that with fractional exponents, we can move the denominator into the root position. Therefore:

(\sqrt[3]{x-4})^4=16

Let's take the fourth root of both sides. Since we're taking an even root, make sure to have the plus-minus symbol!

\sqrt[3]{x-4} =\pm 2

Cube both sides. Since we're cubing, the plus-minus stays.

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Add 4 to both sides.

x=\pm 8+4

Calculator:

x=8+4\text{ or } x=-8+4\\x=12\text{ or } x=-4

So, our answer is A.

And we're done!

7 0
4 years ago
15x – 2(4x + 1) = -9
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