Mulitply second equation by 2 and add to first
3y+2z=12
<u>2y-2z=18 +</u>
5y+0z=30
5y=30
divide 5
y=6
sub back
y-z=9
6-z=9
minus 6
-z=3
times -1
z=--3
x=-3
y=6
So what you do is subtract 4b on both sides so it will be -ax=9+4b then divide x on both sides and you have your answer
Answer:
5 seconds
Step-by-step explanation:
In order to find the time when it landed, we will have to find the x-intercepts.
Equation given to us : -16t² + 48t + 160
Let's take the GCD, which is -16.
-16( t² - 3t - 10 )
Factoring what's inside the brackets, we get the x-intercepts.
What multiples to -10 but adds up to -3? The numbers are -5 and 2
-16 ( t - 5 ) ( t - 2 )
X-intercepts are t - 5 and t - 2
Which is 5 and 2 seconds. But one of this is an extraneous solution and that is 2.
If we substitute the value of 2 in the equation, we will not get 0.
During the x-intercept, the x has a value and y is 0. If we substitute 5 ans x. we will get y as 0.
Hence, the answer is 5 seconds.
Answer:
B
Step-by-step explanation:
Answer:
Step-by-step explanation:
GIVEN: A bicycle training wheel has a radius of 
. The bicycle wheel has a radius of 
.
TO FIND: Approximately how much smaller, in square inches, is the area of the training wheel than the area of the regular wheel.
SOLUTION:
radius of bicycle wheel 
area of bicycle wheel 
putting value,
area of bicycle wheel 
radius of bicycle training wheel 
area of bicycle training wheel
putting value,
area of bicycle wheel 
difference in area of bicycle wheel and bicycle training wheel
hence the training wheel is smaller than regular wheel
