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cestrela7 [59]
2 years ago
8

8 miles in 0.5 hour what rate in miles per hour

Mathematics
2 answers:
yan [13]2 years ago
8 0
In this question it is already given that a person travels 8 miles in 0.5 hours. This is enough information to get to the required answer. Let us first write down all the information's that are already given in the question.
In 0.5 hours the person covers a distance = 8 miles
Then
In 1 hour the person covers a distance of = 8/0.5 miles
                                                                   = 16 miles
So the speed of the person in miles per hour = 16/1 miles/hour
                                                                         = 16 miles per hour
enyata [817]2 years ago
5 0
We can set up a proportion, like this:
\frac{x}{8}= \frac{100}{50}
x (rate of speed per full hour)
over
8 miles
equals
100 percent of an hour
over
50 percent of an hour
when we cross multiply, we get
50x=800
then, we divide both sides by 50 to get:
x=16
so the rate in miles per hour is 16, or 16 miles per hour
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1 / 5040

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3 years ago
The USA Today reports that the average expenditure on Valentine's Day is $100.89. Do male and female consumers differ in the amo
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Answer:

a)\ \ \bar x_m-\bar x_f=67.03\\\\b)\ \ E=15.7416\\\\c)\ \ CI=[51.2884, \ 82.7716]

Step-by-step explanation:

a. -Given that:

n_m=41\ , \ \sigma_m=33, \bar x_m=135.67\\\\n_f=37. \ \ ,\sigma_f=20, \ \ \bar x_f=68.64

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\bar x_m-\bar x_f\\\\\therefore \bigtriangleup\bar x=135.67-68.64\\\\=67.03

Hence, the pointer is estimator 67.03

b. The standard error of the point estimator,\bar x_m-\bar x_f is calculated by the following following:

\sigma_{\bar x_m-\bar x_f}=\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}

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E=z_{\alpha/2}\times \sigma_{\bar x_m-\bar x_f}\\\\\\=z_{0.005}\times\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\\\=2.575\times \sqrt{\frac{33^2}{41}+\frac{20^2}{37}}\\\\\\=15.7416

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\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}

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CI=\bar x_m-\bar x_f\ \pm z_{\alpha/2}\sqrt{\frac{\sigma_m^2}{n_m}+\frac{\sigma_f^2}{n_f}}\\\\=(135.67-68.64)\pm 15.7416\\\\=67.03\pm 15.7416\\\\=[51.2884, \ 82.7716]

Hence, the 99% confidence interval is [51.2884,82.7716]

7 0
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son4ous [18]
Sum means addition:
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Answer:

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7 0
2 years ago
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