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vodomira [7]
3 years ago
11

$7.80/hour = ____ cents/minute? a. 4.7 b. 13 c. 8.8 d. 780

Mathematics
2 answers:
g100num [7]3 years ago
7 0
1$ = 100 cents,    1 hour = 60 minutes

$7.80/hour =  (7.8*100) cents / (1*60)minutes
 
                   =  780 cents/60 minutes
 
                   = 13 cents/minute

<span>Option b.</span>
mr_godi [17]3 years ago
6 0

Answer:

correct option is:

b. 13

Step-by-step explanation:

We know that:

1$ = 100 cents

and 1 hour = 60 minutes

So,

$7.80/hour = (7.8×100) cents / (1×60)minutes

                    = 780 cents/60 minutes

                    = 13 cents/minute

Hence, The correct option is:

b. 13

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Free_Kalibri [48]

Answer:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, ption B is true.

Step-by-step explanation:

Given the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

solving the expression

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}

as

\sqrt{x^2y^3}=xy\sqrt{y}

2\sqrt{x^3y^4}=2xy^2\sqrt{x}

so the expression becomes

\:\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}

Group like terms

                                        =2xy^2\sqrt{x}+xy\sqrt{y}+xy\sqrt{y}

Add similar elements

                                        =2xy^2\sqrt{x}+2xy\sqrt{y}

Therefore, we conclude that:

\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}=2xy^2\sqrt{x}+2xy\sqrt{y}

Hence, option B is true.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
ch4aika [34]

Answer: -258

<u>Step-by-step explanation:</u>

Given the sequence {-8, 16, -32, 64, ... , a₇} we know the following

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Input the information above into the Sum formula:

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shtirl [24]

Answer:

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o-na [289]

Answer:

explicit formula for an, the nth term of the sequence 19,24,29

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Step-by-step explanation:

We need to Write an explicit formula for an, the nth term of the sequence 19,24,29

In the sequence the First term a₁= 19

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The Formula used for explicit formula is: a_1=First \ term ; \ a_n=a_{n-1}+d

Where d is common difference and n is nth term of sequence.

So, explicit formula for an, the nth term of the sequence 19,24,29

a_1=19 ; \ a_n=a_{n-1}+5

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