Group x terms
(2x^2+8x)-12=0
undistribute 2
2(x^2+4x)-12=0
take 1/2 of 4 and square it, add negative and positive of it insde (2^2=4)
2(x^2+4x+4-4)-12=0
factor perfect square
2((x+2)^2-4)-12=0
distribute
2(x+2)^2-8-12=0
2(x+2)^2-20=0
add 20 to both sides
2(x+2)^2=20
divide both sides by 2
(x+2)^2=10
sqrt both sides, remember to take positive and negative root
x+2=+/-√10
minus 2 both sides
x=-2+√10 and -2-√10
Answers:
right 1, down 3 (these two answers only)
Step-by-step explanation:
There are two transformations going on. The first of which is the horizontal or x translation (aka shifting) where the 'x' turns into 'x-1'. This moves the xy axis 1 spot to the left, giving the illusion that the graph moves 1 unit to the right.
The "-3" at the end shifts the graph down 3 units. If g(x) = f(x) - 3, then g(x) is the output of f(x) but 3 less than that, which is why it shifts down 3 units.
i think its 400+10+2+.6+.03+0.008
Hello from MrBillDoesMath!
Answer: B
Remark: It is customary to use x^2, not x2, to indicate the square of x.
Discussion:
(4x + 3) ^ 2= ( 4x)^2 + 2 * (4x)(3) + 3^2 =
16 x^2 + 24x + 9
Thank you,
MrB
Answer:
the picture is not clear
Step-by-step explanation: