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Helen [10]
3 years ago
13

Please help me with this

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

1          7

-120  -22

Step-by-step explanation:

you need to do top left top right bottom left bottom. in order to move x to the other side you need to subtract then divide by the negative.

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Solve the following system of equations using substitution.<br><br> 4x + 2y = 12<br> x = y + 3
BigorU [14]

Answer:

x = 3

y = 0

Step-by-step explanation:

The method of substitution is when one solves an equation for one of the variables, and then substitutes the expression into the other equation. After doing so, one will solve the other equation for the remaining variable and then backsolve for the first variable.

4x + 2y = 12

x = y + 3

The second equation is already sovled for parameter (x), subttiute this into the other equation,

4(y + 3) + 2y = 12

Distribute,

4y + 12 + 2y = 12

Simplify,

6y + 12 = 12

Inverse operations,

6y + 12 = 12

-12

6y = 0

/6

y = 0

Backsolve for (x), substitute the value of (y) into the equation for (x) and solve,

x = y + 3

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x = 3

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3 years ago
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Help pls!! Based on this information, which statement must be true?
choli [55]

Answer:

I am not sure...it's either option 3 or 4....

go with option 4

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3 years ago
What is the measure of each base angle of a 140 degree
trasher [3.6K]

Answer:

The two possible cases are

(i) the base angles are each 40° and the vertex angle is 100°,

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Step-by-step explanation:

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3 years ago
Factorise <br> P(x)= (x+3)(12x^2-3)+(2x-1)(x^2-9)<br> And<br> Q(x)= 4x^4-x^2
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Answer:

a2 answers to exercises

ii. yes. suppose a is negative, so write a = -b where b is positive. let c be a

positive number such that c" = b. then (-c)" = a because (-1)" = -1 since

n is odd.

ii, §1, p. 24

3. x negative, y positive 4. x negative, y negative

ii, §3, p. 33

5. y = -~x + i 6. y = -ix + s 7. x = j2

9 9j3 8. y = --;:;- x + 4 - --;:;- 9. y = 4x - 3 10. y = -2x + 2

",3+3 ",3+3

ii. y= -!x+3+ j'!- 12. y=j3x+s+j3 19. -! 20.-8

21. 2 + j2 22.!<3 + j3) 23. y = (x - n>(j22_ n) + 1

24. y=(x-j2)c~-~)+2 25. y= -(x+ l)(j23+ 1)+2

26. y = (x + 1)(3 + j2) + j2 29. (a) x = -4, y = -7 (b) x = ~, y = i

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ii, §4, p. 35

1.j97 2.j2 3.js2 4.ji3 5.!j5 6.(4,-3) 7. sands 8.(-2,5)

9. sand 7

ii, §8, p. 51

5. (x - 2)2 + (y + 1)2 = 25 6. x 2 + (y - 1)2 = 9 7. (x + \)2 + y2 = 3

8. y + ¥ = 2(x + w 9. y - 1 = (x + 2)2 10. y + 4 = (x - \)2

ii. (x + 1)2 + (y - 2)2 = 2 12. (x - 2)2 + (y - \)2 = 2

13. x + ¥- = 2(y + !)2 14. x-i = (y + 2)2

iii, §1, p. 61

1. 4 2. -2 3. 2 4. i s. -! 6. 0 7. 4 8. 6 9. 3 10. 12 ii. 2

12. 3 13. a

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