1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Helen [10]
3 years ago
13

Please help me with this

Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

1          7

-120  -22

Step-by-step explanation:

you need to do top left top right bottom left bottom. in order to move x to the other side you need to subtract then divide by the negative.

You might be interested in
What is x????<br> please help!!!!
nadya68 [22]

Answer:

x = 9

Step-by-step explanation:

4x + 38 = 10x - 16

The sum of two opposite interior angles is equal to the opposite exterior angle.

4x + 38 = 10x - 16

38 = 10x -16 - 4x

38 = 6x - 16

38 + 16 = 6x

54 = 6x

Divide both sides by 6

x = 9

7 0
2 years ago
Which of the following is an example of overdraft protection?
maxonik [38]

Answer:

(B)  an update from the bank when an account balance is less than $50

Step-by-step explanation:

overdraft occurs when money is withdrawn in excess of what is on the current account. In this situation the account is said to be "overdrawn". This applies to debit cards and how much you have on your balance :)

3 0
2 years ago
Read 2 more answers
Solve for p: √p − 1 − √p = 1
astraxan [27]
<span>√p − 1 − √p = 1
- 1 = 1 (</span>√p is canceled out)<span>
since -1 cant equal 1 so there's no solution</span>
4 0
4 years ago
X-20 = y+20<br>2Y - 44 = X + 22<br>​
nordsb [41]

X-20 = Y+20........    X-Y = 20+20........

X-Y = 40

AND

2Y-44=X+22.............   Y-X= 44+22

Y-X=66

NOW, LET'S FIND X AND Y FROM THESE TWO EQUATIONS....

X-Y =40

Y-X= 66

IF WE COLLECT .......     2Y = 106 AND Y = 53

THEN, USE Y IN ANY EQUATIONS FOR FINDING X

X-53 = 40 ..... X= 53+40 .......... X= 93

X= 93

Y=53

8 0
3 years ago
A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.
Reptile [31]

Answer:

a.P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}

Step-by-step explanation:

We are given that a linear differential equation

y''+2y=e^{3x}+x^3

We have to find the particular solution

P.I=\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}

P.I=\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}

P.I=\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3

P.I=\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0} (higher order terms can be neglected

P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.Characteristics equation

D^2+2=0

D=\pm\sqrt2 i

C.F=C_1cos \sqrt2x+C_2 sin\sqrt2 x

G.S=C.F+P.I

G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)

3 0
3 years ago
Other questions:
  • A trapezoid has an area of 80 square centimeters. If the trapezoid has a base measuring 8 centimeters and a height of 8 centimet
    11·1 answer
  • Shawn bough fruit last week, consisting of 2.26 pounds of bananas,1.5 pounds of grapes, and watermelon that weighed 6.78 pounds.
    5·2 answers
  • you are adding two rational numbers with different signs. how can u tell if the sum will be positive,negative,zero
    9·1 answer
  • {y=2x+14<br> {−4x−y=4<br><br> What can I substitute "y" for in both equations?
    7·1 answer
  • A model of 1.4 x 100
    15·1 answer
  • The ratio of the number of Miki's stickers to the number of Ken's
    12·1 answer
  • This is a Single Choice Question; skip ahead to question content
    7·1 answer
  • A line has a slope of 0 and passes through the point (9,9) what is its equation in slope-intercept form?
    7·1 answer
  • Describe a real-life situation that you can represent with an inequality.
    10·1 answer
  • In a city with a population of 1 million, 500 people have been diagnosed with cancer, whereas the rest of the people do not have
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!